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# 1  
Old 11-22-2013
Menu shell script help
Hi All,

I have written a shell script that show menu driven option.
My requirement is that in the menu driven option i want to select multiple choice.
i.e
if i want to select 1 or 1,2 or 1,2,3 or 2,3 etc ....
Can some one help me in that
My script.
Code:
while true; do
        echo " "
        clear
        echo "------------------------------------------------------"
        echo "    * * * * * * * * Main Menu * * * * * * * * * * *   "
        echo "------------------------------------------------------"
        echo "Please Select An Option given below."
        echo " "
        echo "[1] - TEST1"
        echo " "
        echo "[2] - TEST2"
        echo " "
        echo "[3] - TEST3"
        echo " "
        echo "[4] - ALL"
        echo " "
        echo "[q] - Quit"
        echo " "
        echo "------------------------------------------------------"
        echo -n "Enter your menu choice [1-4]:"

        read "CHOSEN_KEY"
            case $CHOSEN_KEY in

Last edited by Scott; 11-22-2013 at 01:50 AM.. Reason: Please use code tags
This User Gave Thanks to Nawrajesh For This Post:
# 2  
Old 11-22-2013
You could use set with an IFS or comma like this:

Code:
while true; do
echo " "
clear
echo "------------------------------------------------------"
echo " * * * * * * * * Main Menu * * * * * * * * * * * "
echo "------------------------------------------------------"
echo "Please Select An Option given below."
echo " "
echo "[1] - TEST1"
echo " "
echo "[2] - TEST2"
echo " "
echo "[3] - TEST3"
echo " "
echo "[4] - ALL"
echo " "
echo "[q] - Quit"
echo " "
echo "------------------------------------------------------"
echo -n "Enter your menu choice [1-4]:"

read CHOSEN_KEY

OIFS=$IFS
IFS=","
set -- $CHOSEN_KEY
IFS=$OIFS

while [ $# -ge 1 ]
do
    CHOSEN_KEY=$1
    shift
    case "$CHOSEN_KEY" in
       1) echo TEST1 ;;
       2) echo TEST2 ;;
       3) echo TEST3 ;;
       4) set 1 2 3 $@ ;;
       q) exit 0 ;;
       *) echo Invalid option $CHOSEN_KEY ;;
    esac
done
sleep 2
done

# 3  
Old 11-22-2013
Hi Chubler_XL,

I will test that and will get back.

anyways thanks for the prompt response.

Regards,
Rajesh

---------- Post updated at 11:12 AM ---------- Previous update was at 10:47 AM ----------

Hi Chubler_XL ,

Thanks Now i am able to do multiple selections.
but now if i out if condition in in selection 1 or selection 2 i am getting below error.

Code:
./testing.sh
./testing.sh: line 35: syntax error near unexpected token `['
./testing.sh: line 35: `          if [ $CHOSEN_KEY == 1 ];'

Can you please help me out for this
Scripts:

Code:
while true; do
echo " "
clear
echo "------------------------------------------------------"
echo " * * * * * * * * Main Menu * * * * * * * * * * * "
echo "------------------------------------------------------"
echo "Please Select An Option given below."
echo " "
echo "[1] - TEST1"
echo " "
echo "[2] - TEST2"
echo " "
echo "[3] - TEST3"
echo " "
echo "[4] - ALL"
echo " "
echo "[q] - Quit"
echo " "
echo "------------------------------------------------------"
echo -n "Enter your menu choice [1-4]:"

read CHOSEN_KEY

OIFS=$IFS
IFS=","
set -- $CHOSEN_KEY
IFS=$OIFS

while [ $# -ge 1 ]
do
    CHOSEN_KEY=$1
    shift
    case "$CHOSEN_KEY" in
       1) echo TEST1 ;;
          if [ $CHOSEN_KEY == 1 ];
          then
          echo "Select Version"
          echo "[a] - Version 6"
          echo "[b] - Version 7"
          echo "Please enter your option: "
          read "CHOSEN_VER"
          if [ $CHOSEN_VER == a ];
          then
          echo " You have chosen Version 6 installation "
          elif [ $CHOSEN_VER == b ];
          then
          echo " You have chosen Version 7 installation "
          else
          echo "Select proper category"
          fi
          fi
          break;;
       2) echo TEST2 ;;
          if [ $CHOSEN_KEY == 1 ];
          then
          echo "Select Version"
          echo "[a] - Version 6"
          echo "[b] - Version 7"
          echo "Please enter your option: "
          read "CHOSEN_VER"
          if [ $CHOSEN_VER == a ];
          then
          echo " You have chosen Version 6 installation "
          elif [ $CHOSEN_VER == b ];
          then
          echo " You have chosen Version 7 installation "
          else
          echo "Select proper category"
          fi
          fi
          break;;
       3) echo TEST3 ;;
       4) set 1 2 3 $@ ;;
       q) exit 0 ;;
       *) echo Invalid option $CHOSEN_KEY ;;
    esac
done
sleep 2
done

 



read CHOSEN_KEY

OIFS=$IFS
IFS=","
set -- $CHOSEN_KEY
IFS=$OIFS

while [ $# -ge 1 ]
do
    CHOSEN_KEY=$1
    shift
    case "$CHOSEN_KEY" in
       1) echo TEST1 ;;
          if [ $CHOSEN_KEY == 1 ];
          then
          echo "Select Version"
          echo "[a] - Version 6"
          echo "[b] - Version 7"
          echo "Please enter your option: "
          read "CHOSEN_VER"
          if [ $CHOSEN_VER == a ];
          then
          echo " You have chosen Version 6 installation "
          elif [ $CHOSEN_VER == b ];
          then
          echo " You have chosen Version 7 installation "
          else
          echo "Select proper category"
          fi
          fi
          break;;
       2) echo TEST2 ;;
          if [ $CHOSEN_KEY == 1 ];
          then
          echo "Select Version"
          echo "[a] - Version 6"
          echo "[b] - Version 7"
          echo "Please enter your option: "
          read "CHOSEN_VER"
          if [ $CHOSEN_VER == a ];
          then
          echo " You have chosen Version 6 installation "
          elif [ $CHOSEN_VER == b ];
          then
          echo " You have chosen Version 7 installation "
          else
          echo "Select proper category"
          fi
          fi
          break;;
       3) echo TEST3 ;;
       4) set 1 2 3 $@ ;;
       q) exit 0 ;;
       *) echo Invalid option $CHOSEN_KEY ;;
    esac
done
sleep 2
done

Regards,
Rajesh
Last edited by Scott; 11-22-2013 at 01:50 AM.. Reason: Code tags
# 4  
Old 11-22-2013
It's best practice to have both the string in double quotes whenever you do string comparision
Code:
if [ "$CHOSEN_VER" == "a" ];

and use numeric comparision operator for numeric as below
Code:
if [ $CHOSEN_VER -eq 1 ];

# 5  
Old 11-22-2013
Hi ,
Still same error.

Code:
./testing.sh
./testing.sh: line 35: syntax error near unexpected token `['
./testing.sh: line 35: `          if [ $CHOSEN_KEY -eq 1 ];'

Code:
while [ $# -ge 1 ]
do
    CHOSEN_KEY=$1
    shift
    case "$CHOSEN_KEY" in
       1) echo TEST1 ;;
          if [ $CHOSEN_KEY -eq 1 ];
          echo TEST1 ;;
          then
          echo "Select Version"
          echo "[a] - Version 6"
          echo "[b] - Version 7"
          echo "Please enter your option: "
          read "CHOSEN_VER"
          if [ "$CHOSEN_VER" == "a" ];
          then
          echo " You have chosen Version 6 installation "
          elif [ "$CHOSEN_VER" == "b" ];
          then
          echo " You have chosen Version 7 installation "
          else
          echo "Select proper category"
          fi
          fi
          break;;

---------- Post updated at 11:52 AM ---------- Previous update was at 11:39 AM ----------

Hi all ,
above problem solved but now when I select 2 options i,.e 1,2 it only echo for 1st option.
Please fin the output.

Code:
./testing.sh
------------------------------------------------------
 * * * * * * * * Main Menu * * * * * * * * * * *
------------------------------------------------------
Please Select An Option given below.

[1] - TEST1

[2] - TEST2

[3] - TEST3

[4] - ALL

[q] - Quit

------------------------------------------------------
Enter your menu choice [1-4]:1,2
You have Select 1 , now please select 1 Version
[a] - Version 6
[b] - Version 7
Please enter your option:
a
 You have chosen Version 6 installation

Script:-
Code:
while true; do
echo " "
clear
echo "------------------------------------------------------"
echo " * * * * * * * * Main Menu * * * * * * * * * * * "
echo "------------------------------------------------------"
echo "Please Select An Option given below."
echo " "
echo "[1] - TEST1"
echo " "
echo "[2] - TEST2"
echo " "
echo "[3] - TEST3"
echo " "
echo "[4] - ALL"
echo " "
echo "[q] - Quit"
echo " "
echo "------------------------------------------------------"
echo -n "Enter your menu choice [1-4]:"

read CHOSEN_KEY

OIFS=$IFS
IFS=","
set -- $CHOSEN_KEY
IFS=$OIFS

while [ $# -ge 1 ]
do
    CHOSEN_KEY=$1
    shift
    case "$CHOSEN_KEY" in
       1) if [ $CHOSEN_KEY -eq 1 ];
          then
          echo "You have Select $CHOSEN_KEY , now please select $CHOSEN_KEY Version"
          echo "[a] - Version 6"
          echo "[b] - Version 7"
          echo "Please enter your option: "
          read "CHOSEN_VER"
          if [ $CHOSEN_VER == a ];
          then
          echo " You have chosen Version 6 installation "
          elif [ $CHOSEN_VER == b ];
          then
          echo " You have chosen Version 7 installation "
          else
          echo "Select proper category"
          fi
          fi
          break;;
       2) if [ $CHOSEN_KEY == 2 ];
          then
          echo "You have Select $CHOSEN_KEY , now please select $CHOSEN_KEY Version"
          echo "[a] - Version 6"
          echo "[b] - Version 7"
          echo "Please enter your option: "
          read "CHOSEN_VER"
          if [ $CHOSEN_VER == a ];
          then
          echo " You have chosen Version 6 installation "
          elif [ $CHOSEN_VER == b ];
          then
          echo " You have chosen Version 7 installation "
          else
          echo "Select proper category"
          fi
          fi
          break;;
       3) echo TEST3 ;;
       4) set 1 2 3 $@ ;;
       q) exit 0 ;;
       *) echo Invalid option $CHOSEN_KEY ;;
    esac
done
sleep 2
done

Regards,
Rajesh

Moderator's Comments:
Mod Comment I would recommend that you read the private messages you have received regarding the use of code tags...
Last edited by Scott; 11-22-2013 at 02:15 AM.. Reason: Code tags, please...
# 6  
Old 11-22-2013
Quote:
Originally Posted by Nawrajesh
Hi ,
Still same error.

Code:
./testing.sh
./testing.sh: line 35: syntax error near unexpected token `['
./testing.sh: line 35: `          if [ $CHOSEN_KEY -eq 1 ];'

Code:
while [ $# -ge 1 ]
do
    CHOSEN_KEY=$1
    shift
    case "$CHOSEN_KEY" in
       1) echo TEST1 ;;
          if [ $CHOSEN_KEY -eq 1 ];
          echo TEST1 ;;
          then
          echo "Select Version"
          echo "[a] - Version 6"
          echo "[b] - Version 7"
          echo "Please enter your option: "
          read "CHOSEN_VER"
          if [ "$CHOSEN_VER" == "a" ];
          then
          echo " You have chosen Version 6 installation "
          elif [ "$CHOSEN_VER" == "b" ];
          then
          echo " You have chosen Version 7 installation "
          else
          echo "Select proper category"
          fi
          fi
          break;;

There are several problems here. Note the code marked in red above.

First the 1st ";;" on the first line of the actions for case 1 terminates the actions for that case. Having an if statement following that is not allowed. I assume you should just remove this ";;".

Second, you are in the actions to be performed when $CHOSEN_KEY expands to 1; so why do you need to test whether $CHOSEN_KEY still expands to 1 one line later?

Third, you have an echo statement after an if statement before the then keyword. And, it ends with another ";;".

I'm guessing you want something more like:
Code:
while [ $# -ge 1 ]
do
    CHOSEN_KEY="$1"
    shift
    case "$CHOSEN_KEY" in
    (1) echo TEST1
        echo 'Select Version'
        echo '[a] - Version 6'
        echo '[b] - Version 7'
        printf 'Please enter your option: '
        read CHOSEN_VER
        if [ "$CHOSEN_VER" = "a" ]
        then
            echo ' You have chosen Version 6 installation'
        elif [ "$CHOSEN_VER" = "b" ]
        then
            echo ' You have chosen Version 7 installation'
        else
            echo 'Select proper category'
            # I am surprised that you do not exit here instead of continuing???
        fi
        break;;

# 7  
Old 11-22-2013
Hi All,

thanks for the reply.
when i select two option and hit enter the output show only for 1st selection and not for the second .
below check below output.
Code:
------------------------------------------------------
 * * * * * * * * Main Menu * * * * * * * * * * *
------------------------------------------------------
Please Select An Option given below.

[1] - TEST1

[2] - TEST2

[3] - TEST3

[4] - ALL

[q] - Quit

------------------------------------------------------
Enter your menu choice [1-4]:1,2
TEST1

Script:-
Code:
while true; do
echo " "
clear
echo "------------------------------------------------------"
echo " * * * * * * * * Main Menu * * * * * * * * * * * "
echo "------------------------------------------------------"
echo "Please Select An Option given below."
echo " "
echo "[1] - TEST1"
echo " "
echo "[2] - TEST2"
echo " "
echo "[3] - TEST3"
echo " "
echo "[4] - ALL"
echo " "
echo "[q] - Quit"
echo " "
echo "------------------------------------------------------"
echo -n "Enter your menu choice [1-4]:"

read CHOSEN_KEY

OIFS=$IFS
IFS=","
set -- $CHOSEN_KEY
IFS=$OIFS

while [ $# -ge 1 ]
do
    CHOSEN_KEY=$1
    shift
    case "$CHOSEN_KEY" in
       1) echo TEST1
          if [ $CHOSEN_KEY -eq 1 ];
          then
          echo "You have Select $CHOSEN_KEY , now please select $CHOSEN_KEY Version"
          echo "[a] - Version 6"
          echo "[b] - Version 7"
          echo "Please enter your option: "
          read "CHOSEN_VER"
          if [ $CHOSEN_VER == a ];
          then
          echo " You have chosen Version 6 installation "
          elif [ $CHOSEN_VER == b ];
          then
          echo " You have chosen Version 7 installation "
          else
          echo "Select proper category"
          fi
          fi
          exit ;
          break;;

       2) echo TEST2
          if [ $CHOSEN_KEY == 2 ];
          then
          echo "You have Select $CHOSEN_KEY , now please select $CHOSEN_KEY Version"
          echo "[a] - Version 6"
          echo "[b] - Version 7"
          echo "Please enter your option: "
          read "CHOSEN_VER"
          if [ $CHOSEN_VER == a ];
          then
          echo " You have chosen Version 6 installation "
          elif [ $CHOSEN_VER == b ];
          then
          echo " You have chosen Version 7 installation "
          else
          echo "Select proper category"
          fi
          fi
          exit ;
          break;;

       3) echo TEST3 ;;
       4) set 1 2 3 $@ ;;
       q) exit 0 ;;
       *) echo Invalid option $CHOSEN_KEY ;;
    esac
done
sleep 2
done

Last edited by Scott; 11-22-2013 at 04:23 AM.. Reason: Use code tags, PLEASE...
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