How to monitor process that consumes 100% during more than 01 hour ?


 
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# 8  
Old 11-12-2013
Hi,

Than's for your input.

Have you got a sample on syntax on how to implement awk command : "to check for a non-zero leading (sub)field in the time rather than just checking if it exists" ?

Regards,
# 9  
Old 11-12-2013
Depending how your awk handles field splitting, you might be able to just do:
Code:
awk '$2>1' FS=":| "

Alternatively, you could use split:
Code:
awk '{split($2,times,":"); if (times[1]>1) {print}}'

(That's just outputting the rows, of course - you'd need to adapt it).
# 10  
Old 11-12-2013
You can replace my previous ERE :.+: by [-1-9][0-9]*:.+:
That will match only if there is a leading non-zero number.

---------- Post updated at 04:29 AM ---------- Previous update was at 04:23 AM ----------

However, my previous idea is not fully correct.
It will not catch processes that have run normally for some time then start to consume CPU time.

Last edited by MadeInGermany; 11-12-2013 at 04:02 PM.. Reason: Added a - to the charset to include e.g. 1-00:00:00
# 11  
Old 11-12-2013
Also, you might want to look at process accounting (psacct on RHEL, iirc).
# 12  
Old 11-12-2013
Here is an improved ps command.
It reports the processes that have accumulated 1 hour CPU time and still consuming CPU time. There is a high probability that the CPU time was accumulated within the last hour.
Code:
ps -eo pid,time,pcpu,args | awk '$2~/[-1-9][0-9]*:.+:/ && $3>50.0'

NB pcpu is currently per CPU on Linux (while e.g. on Solaris it is per system, i.e. divided by the number of virtual CPUs).
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