Shell Programming and Scripting

This may be such a simple problem but I don't know what am I doing wrong.
The program I'm trying to do is

Code:

for pdb in $(ls *.pdb)
do

res=$(grep 'TYPE   2' $pdb | awk ' {print $1} ')
pos=${res/.pdb:REMARK/} > Type_List.txt

done

sec=$(grep 'STANDARD' $res | awk ' {print $4} ')
ls $sec >> Type_List.txt

This script is to list $pos and $sec creating a new file, both are related to many other files in the same directory (those *.pdb)

Thank you for your help

Few suggestions:
skip ls in for loop.
use

Code:

awk '/TYPE   2/ {print $1}' 
awk ' /STANDARD/ {print $4} '

instead of
grep & awk .

$res will have only one value after exiting the for loop. Not sure , if that's what you want.

I appreciate, if you can post input sample and desired output .

In addition to what greet_sed has already said:

Code:

for pdb in $(ls *.pdb)

is an inefficient way of implementing:

Code:

for pdb in *.pdb

If you don't show us the format of your input files (and provide a sample of one of your input files) and show us the results you are trying to obtain, we can't do much to help you.

What you have given us so far is basically: I want to create a file that is related to some other files. It isn't working. Fix it for me.

I'm afraid that we aren't omniscient enough to discern what output you want. Please help us help you!

This statement confuses me:

Code:

pos=${res/.pdb:REMARK/} > Type_List.txt

What do you think this is doing in the for loop?