[Solved] Compare column data in all the rows

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# 1  
Old 10-09-2013
[Solved] Compare column data in all the rows


In the below sorted input file.. I am comparing the first 3 columns of data one by one row and it is a pipeline delimitter file..

If first 3 columns of data matches with any record in the file the expected
output will be


I know it will be possible through awk command.. please help on this

---------- Post updated at 06:20 PM ---------- Previous update was at 04:46 PM ----------


I have just tried and it got worked the below script.. But i need in one line of command by using "awk"..

rm opfile
cut -d'|' -f1-3 $inputfile | sort | uniq  > temp
NumOfRec=`wc -l < temp`
while [ $t -le $NumOfRec ]
 rec=`head -$t temp | tail -1`
 grep "$rec" $inputfile | awk -F'|' '{print $4}' | tr -s  '\n' ',' | read lastcol
 echo "$rec|$lastcol" >> opfile
 t=`expr $t \+ 1`

Last edited by vbe; 10-09-2013 at 10:17 AM.. Reason: corrected faulty code to icode tags
# 2  
Old 10-09-2013
Your original requested output doesn't match your requirement.

It should be:
awk -F\| '{
  X=$1$2$3; A[X]?A[X]=A[X]","$NF:A[X]=$0
  for( a in A )
    print A[a]
}' file

This User Gave Thanks to Scott For This Post:
# 3  
Old 10-09-2013
Hats off to you Scott it's really a nice code.

R. Singh
# 4  
Old 10-09-2013
One more awk approach you may try

$ cat test

$ awk -F'[|]' '{++i;printf(!_[$1$2$3]++)?$0 ",":((++i)<3)?($1=$2=$3="")$4 "," : $4 RS;i--}' test


Last edited by Akshay Hegde; 10-09-2013 at 10:54 AM.. Reason: tag
# 5  
Old 10-09-2013
Thanks a lot Scott.
Ya I noticed the orginal output and i wrongly typed into that.
Could you explain the command bit detail.. so it will useful if i get these type of scenarios to work next time..

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