Shell Programming and Scripting

Hi everyone,

I need to search files starting with RPT_0, RPT_1,........ in a directory. How can I implement that through a shell script. Also I want to read the last line of each file after searching them. Can someone help me out in this regard.

One more thing how I can extract a particular pattern in the last line of the file.
Eg: ### Job 65 (RPT507A BBW ): 390 lines, 7 pages, 10/26/2005 01:55:16
In the above line I have extract RPT507A BBW and convert that space between RPT507A and BBW with underscore( _ ).

Thanks in advance...
srivsn

Will this help you??

Code:

for i in `ls -1 RPT_*`
do
last=`tail -1 $i`
pat=`expr "$last" : '.*(\(.*\)).*'`
pat=`echo $pat | sed 's/ /_/'`
print $pat
done

Hi everyone,

Thx a lot Mona for your reply. It worked.

Little modifications. I am extremely new to this Unix. Please help.

After extracting the name from the code below, I want to move the contents of the old file to the new one extracted. We have to delete the old file. Also concatinate the new file name with DD(current day). I will give you a example below.

RPT_1.txt(old filename)
### Job 65 (RPT507A BBW ): 390 lines, 7 pages, 10/26/2005 01:55:16(last line of file RPT_1.txt)

By using the logic given in reply mail, I will get the output as RPT507A_BBW

Now I want to concatinate that with DD(day).
So my output is RPT507A_BBW09 (09 is today)

Also I want to append all the files in RPT_1.txt to new filename RPT507A_BBW09
and delete the old file RPT_1.txt.

The same logic has to be implemented for all the files in the directory starting with RPT_*.txt.

Thanks to all,
srivsn

Code:

day=$(date +%d)
for i in `ls -1 RPT_*`
do
last=`tail -1 $i`
pat=`expr "$last" : '.*(\(.*\)).*'`
pat=`echo $pat | sed 's/ /_/'`
pat=$pat$day
mv $i $pat
done

Hi Mona/everyone,

Thx again for Mona . I need to pass RPT_ as parameter to the shell script which I have below. Say I have created a shell script rn.sh with the code in last reply. Now instead of RPT_ hard coding, I need to give a parameter there and I am using this script in some other job. There I will give the parameter value which includes path name along file name(RPT_). Could you help me in this.....Please give the syntax also.

Thanks,
srivsn

This is very simple. Just pass "RPT_" as a parameter to your script. Change the for loop alone like below

Code:

for i in `ls -1 $1*`

Hi Mona,

Thx a lot. It worked. Can you tell me how to split a large file when it came across a pattern like "###" in the beginning of the line.
Eg: ### Job 65 (RPT507A BBW ): 390 lines, 7 pages, 10/26/2005 01:55:16

I have multiple lines like the one above in a single file. I have to split the file into number of files when I came across ### at the beginning of the line and store the lines including the ### line in a temporary file. Please help.

Thx in advance........
srivsn