Shell Programming and Scripting

file1
more file
file4

date1
date 2
date 3

user1  
user2
sam jackson

file1 date1 user1
more file date 2 user2
file4 date3  same jackson

#!/bin/bash

a="aa bb cc dd ee"
b="11 22 33 44 55"
c="AA BB CC DD EE"

for segment in 1 2 3 4 5; do
  echo $a | cut -d' ' -f${segment} | tr -d "\n"
  echo " "  | tr -d "\n"
  echo $b | cut -d' ' -f${segment} | tr -d "\n"
  echo " "  | tr -d "\n"
  echo $c | cut -d' ' -f${segment}
done

ar=($a); br=($b); cr=($c)
for((i=0;i<5;i++)); 
do   
  printf "${ar[i]} ${br[i]} ${cr[i]}\n"
done

paste -d' ' <(echo $a| tr ' ' '\n') <(echo $b|tr ' ' '\n') <(echo $c|tr ' ' '\n')

#!/bin/bash

a="aabbccddee"
b="1122334455"
c="AABBCCDDEE"

for segment in 1 3 5 7 9; do
  echo  $a | cut -c${segment}-`expr ${segment} + 1` | tr -d "\n"
  echo  " "  | tr -d "\n"
  echo  $b | cut -c${segment}-`expr ${segment} + 1` | tr -d "\n"
  echo  " "  | tr -d "\n"
  echo  $c | cut -c${segment}-`expr ${segment} + 1`
done

d="$a
$b
$c"

echo "$d"
file1
more file
file4
date1
date 2
date 3
user1
user2
sam jackson

awk '{a[++t]=$0} END {for (i=1;i<=3;i++) print a[i],a[i+3],a[i+6]}' <<<"$d"
file1 date1 user1
more file date 2 user2
file4 date 3 sam jackson