Split line of file from delimeter.

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# 1  
Old 09-18-2013
Split line of file from delimeter.

I have a below file.

select * from customer
MERGE INTO Archive; delete from Employee; using select * from customer; 
delete from employee; select * from Employee;
insert into employee(1,1);

select * from customer
delete from Employee
using select * from customer
delete from employee
select * from Employee
insert into employee(1,1)

I want to split the line from deimeter semicolun `;`
& each statement in single line.
It might be happen that Semicolon is not comming in line or not comming.

I try this with CUT command but it will work only on single line.

Last edited by Franklin52; 09-18-2013 at 07:16 AM.. Reason: Please use code tags
# 2  
Old 09-18-2013
tr -s ';' '\n' < infile

# 3  
Old 09-18-2013
sed 's/; *$//; s/; */\
/g' file

Last edited by MadeInGermany; 09-18-2013 at 06:11 AM..
# 4  
Old 09-18-2013
try also:
awk '$1=$1' RS=";|\n" input_file

This User Gave Thanks to rdrtx1 For This Post:
# 5  
Old 09-18-2013
Another gawk/mawk (only gawk / mawk support a regex in RS instead of a single character) :
mawk NF RS="; *|\n" file

@rdrtx1: Using $1=$1 like that can be tricky if a $1 happens to be 0 (zero) or 0.0 for example..

Last edited by Scrutinizer; 09-18-2013 at 05:57 PM..
# 6  
Old 09-19-2013
This should be OK in all awk, but needed two awk Smilie
awk '{gsub(/; */,"\n")}1' file | awk NF

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