Perl equivalent substitution

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# 1  
Old 09-17-2013
Perl equivalent substitution

hi Geeks,
my input file contains data like =>
[] 53 - Deewana Kar Raha Hai.mp3
[] 54 - Hale Dil.mp3
[] 55 - Ishq Sufiyana.mp3
[] 56 - Abhi Kuch Dino Se.mp3
[] 57 - Pee Loon Hoto Ki Sargam.mp3

I had used sed command to remove the prefix from the file name like
sed 's/^\[.*- \(.*.mp3\)/\1/' file

it gives me the perfect result. but now I want the same result by using the perl substitution.

I tried this command
perl -e 's/^\[.*- \(.*.mp3\)/\1/' file

but unfortunately it doesn't return anything and echo $? returns 0.

Kindly advise .. thanks in advance.


Last edited by Scott; 09-17-2013 at 03:04 PM.. Reason: Code tags
# 2  
Old 09-17-2013
perl -pe 's/^\[.*- \(.*.mp3\)/\1/' file

This User Gave Thanks to bartus11 For This Post:
# 3  
Old 09-17-2013
I don't think you need to escape ( in a perl regex. But perl -e doesn't work that way, it expects a perl program, not a sed statement.

Your regex looks more complicated than it needs to be, though -- why match the entire name, and put back part of it, instead of just matching the part you want to delete? Then you don't need any of sed or perl's advanced features.

$ echo "[a b c d e f g] qwerty.mp3" | sed 's/^\[[^]]*\] *//'



This User Gave Thanks to Corona688 For This Post:
# 4  
Old 09-17-2013
Right. Brackets' escapes are unnecessary in Perl regexes:
perl -pe 's/^\[.*- (.*.mp3)/\1/' file

This User Gave Thanks to bartus11 For This Post:
# 5  
Old 09-18-2013
thank you very much guys Smilie
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