Rename folder


 
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# 15  
Old 09-16-2013
thx a lot man

---------- Post updated at 06:36 AM ---------- Previous update was at 06:27 AM ----------
for these kind of directories like
Code:
P3 ( 9 - 10 ) = 111

P2 ( 13 - 11 ) = 112

P3 ( 4 - 8 ) = 114

for some reasons i've changed a bit that script

i used awk to detect d1 and d2

Code:
d1=$(echo  "$i" |awk '{print  $3}'|sed 's/\.//')
d2=$(echo  "$i" |awk '{print  $5}' | sed 's/\.//')

instead of

Code:
read d1 d2 < <(echo "$i" | sed 's/ //g;s/.*(\([0-9.]\+\)-\([0-9.]\+\))/\1 \2/;s/\./:/g')

and then


Code:
m1=$(date --date="${d1} 10 minutes " "+%H.%M")
 m2=$(date --date="${d2} 10 minutes " "+%H.%M")

and then i used awk to substitute new values with old values


Code:
j=$(echo "$i1" |awk '{gsub($3,"$m1",$3) && gsub($5,"$m2",$5); print }')

instead of


Code:
j=$(echo "$i" | sed 's/\(.*( *\)'$d1'\( *- *\)'$d2'\( *)\)/\1'$m1'\2'$m2'\3/')

but my problem is with awk after substitution output is like
P3 ( $m1 - $m2 ) = 114

instead of replacing m1 and m2 with their values .

how can i use awk or sed to substitution m1 and m2 with old values for these kind of directories

P3 ( 4 - 8 ) = 114

P3 ( 8.30 - 11.30 ) = 113
# 16  
Old 09-16-2013
Just replace:
Code:
j=$(echo "$i1" |awk '{gsub($3,"$m1",$3) && gsub($5,"$m2",$5); print }')

by
Code:
j=$(echo "$i1" |awk '{gsub($3,"'$m1'",$3) && gsub($5,"'$m2'",$5); print }')

should work.

I edit this post to correct: double quote must in simple quote.

Regards.

Last edited by disedorgue; 09-16-2013 at 10:12 AM.. Reason: shift simple quote in red
# 17  
Old 09-16-2013
Quote:
Originally Posted by disedorgue
Just replace:
Code:
j=$(echo "$i1" |awk '{gsub($3,"$m1",$3) && gsub($5,"$m2",$5); print }')

by
Code:
j=$(echo "$i1" |awk '{gsub($3,"'$m1'",$3) && gsub($5,"'$m2'",$5); print }')

should work.

I edit this post to correct: double quote must in simple quote.

Regards.
thx a million man . you are awesome !!
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