Help with bash script problem

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# 1  
Old 09-05-2013
Help with bash script problem


Below is my bash script:

if [ $1 !~/+/ ] && [ $2 !~/+/ ]; then
Number_Count_Program $1.results $2.results > $1.$2.counts
Number_Split_Program $1.results $2.results > $1.$2.split

After I run the following command:
./ A B
./ line 1: [: A: unary operator expected

Anybody advice to edit my bash script, ?

The purpose I write the bash script is automatic the server run "Number_Count_Program" if first and second argument key in is don't have any "+";
As long as either first or second argument got "+", it will run "Number_Split_Program".

"Number_Count_Program" and "Number_Split_Program" is an c++ program which worked well.
Thanks for any advice.
# 2  
Old 09-06-2013
if [[ $1 =~ \+ ]] && [[ $2 =~ \+ ]]; then
 echo "got two +'s"
 echo "didn't get two +'s"

You can use ! before the tests to negate if you must have it the other way around.
# 3  
Old 09-06-2013
Try something like the following:

if [[ $1 =~ "+"  &&  $2 =~ "+" ]]
     echo "Match"
     echo "No Match"

This User Gave Thanks to fpmurphy For This Post:
# 4  
Old 09-06-2013
Hi Scott,

I just try your code edit.
But it seems like the script will run "Number_Count_Program" if I key in something like "./ A+B B+C"?

What I prefer is "Number_Count_Program" is run only when both first and second argument don't have any "+".
If either first or second or both got "+", I will prefer it run "Number_Split_Program".

Kindly correct me if I was wrong.
# 5  
Old 09-06-2013
You will have to negate the tests, or swap around the code in your if "then" and "else" blocks.
This User Gave Thanks to Scott For This Post:
# 6  
Old 09-06-2013
The + is special in an ERE.
I found it is necessary to quote and escape the +
if [[ $1 =~ "\+" && $2 =~ "\+" ]]; then

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