Update field value on a csv file


 
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# 1  
Old 08-28-2013
Update field value on a csv file

Hi
I have a job status csv file. I want to update the status of the job in the file.
Below is the csv file
Code:
 
1,jobname1,in_progress,starttime,somthing,somthing
2,jobname2,completed,starttime,somthing,somthing
3,jobname3,failed,starttime,somthing,somthing
4,jobname1,not_started,starttime,somthing,somthing

I want to update the status of the job in the file for a pattern "1,jobname1" from in_progress to completed. Basically i want to update the 3rd field value (what ever it may be) of the line which matches the pattern "1,jobname1" with "completed"

ie, after the update the file should look like
Code:
 
1,jobname1,completed,starttime,somthing,somthing
2,jobname2,completed,starttime,somthing,somthing
3,jobname3,failed,starttime,somthing,somthing
4,jobname1,not_started,starttime,somthing,somthing

can I do this with awk ?
Thanks
# 2  
Old 08-28-2013
Code:
awk -F, '/1,jobname1,in_progress/ {$3="completed"} 1' filename

This User Gave Thanks to krishmaths For This Post:
# 3  
Old 08-28-2013
Quote:
Originally Posted by krishmaths
Code:
awk -F, '/1,jobname1,in_progress/ {$3="completed"} 1' filename

Thanks for the reply

I can take only "1,jobname1" as the search string and i want update any column on that line.

ie, I would like to search with string "1,jobname1" and update 3rd column with "completed" and 5th column with date +"%Y%m%d%H%M%S"
# 4  
Old 08-28-2013
Code:
awk -F, 'BEGIN{"date +\"%Y%m%d%H%M%S\""|getline d} /1,jobname1/{$3="completed";$5=d} 1' filename

This User Gave Thanks to krishmaths For This Post:
# 5  
Old 08-28-2013
Quote:
Originally Posted by krishmaths
Code:
awk -F, 'BEGIN{"date +\"%Y%m%d%H%M%S\""|getline d} /1,jobname1/{$3="completed";$5=d} 1' filename


this is working fine for me... Thanks a lot

is it possible to pass the value in a variable. I tried the below

Code:
 
awk -F, '/1,jobname1/ {$3="completed";$5="${temp_date}"} 1' OFS="," file

but instead of assigning the value from variable temp_date, I'm getting the string "${temp_date}" in the result.
# 6  
Old 08-28-2013
You need to use awk variable like this:

Code:
awk -F, -v td=$temp_date '/1,jobname1/ {$3="completed";$5=td} 1' OFS="," file

This User Gave Thanks to krishmaths For This Post:
# 7  
Old 08-28-2013
Quote:
Originally Posted by krishmaths
You need to use awk variable like this:

Code:
awk -F, -v td=$temp_date '/1,jobname1/ {$3="completed";$5=td} 1' OFS="," file

Thanks, its working for me

---------- Post updated at 01:25 PM ---------- Previous update was at 05:45 AM ----------

Quote:
Originally Posted by krishmaths
You need to use awk variable like this:

Code:
awk -F, -v td=$temp_date '/1,jobname1/ {$3="completed";$5=td} 1' OFS="," file


is it possible to pass the pattern in a variable

Code:
pattern_str="1,jobname1"
awk -F, -v td=$temp_date '/$pattern_str/ {$3="completed";$5=td} 1' OFS="," file


Last edited by vgersh99; 08-28-2013 at 03:56 PM..
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