File watcher script

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# 1  
Old 08-27-2013
File watcher script

if test -n "$(find/data/path/ 'filename.txst' -print-quit)
  echo "file found"
  exit 0
  echo "file not found"
  exit 46

So I basically looking to understand the
if test -n "$(find/data/path/ 'filename.txst' -print-quit)

Pls help to elaborate what this command is doing.

Last edited by Scott; 08-27-2013 at 09:15 PM.. Reason: Code tags
# 2  
Old 08-27-2013
I think it must be find /data/path, not find/data/path. Also, -print -quit not -print-quit

What it does is it looks inside /data/path for all files named 'filename.txst' (did you mean txt?) and prints their names. The -quit makes it exit after it prints the first name.

So it's looking for the first file it can find named filename.txst.
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# 3  
Old 08-27-2013
Thanks alot

---------- Post updated at 02:47 PM ---------- Previous update was at 02:41 PM ----------

what does this code mean
Any help appreciate...

base_file=$(basename $latest_file)

Last edited by Scott; 08-27-2013 at 09:16 PM.. Reason: Code tags
# 4  
Old 08-27-2013
Returns the base file name of a string parameter.

Basically it strips out the extra stuff and just gives you the file name:

 basename /u/dee/desktop/


You can do a
man basename

to get more info on your system. The man pages are your friend.
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# 5  
Old 08-27-2013
It removes /path/to/ from /path/to/file and just gives you 'file'.
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# 6  
Old 08-27-2013
Along with above this is another code line, which I am unabel to understood, because there is no rc_1 is define in the script above..

echo 'Return Code Basename :' $rc_1
echo '+-------------------------------+'

Last edited by Scott; 08-27-2013 at 09:16 PM.. Reason: Code tags [7th time]
# 7  
Old 08-27-2013
Please use code tgs as required by forum rules!

The rc_1 is defined in that snippet you post, by assigning the last command's (or pipe's) exit code to it. Read the man page of your shell.
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