Add a character C in a column if that column is blank

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# 15  
Old 08-26-2013
Hi scrutinizer,

Thank you very much for your help. When I use a~/[A-Z]/ I got the correct result.

---------- Post updated at 03:43 AM ---------- Previous update was at 03:31 AM ----------

Hi Jotne

a~/[[:alpha:]]/ doesn't work.
# 16  
Old 08-26-2013
Strange, what does awk --version produce?
# 17  
Old 08-26-2013
I haven't seen anything yet saying what OS is being used here, but the following slightly simpler awk script may do what is wanted:
awk '{a=substr($0,17,1); a=(a!=" ")?a:"C"; print substr($0,1,16) a substr($0,18)}' file

If you are using a Solaris/SunOS system, use /usr/xpg4/bin/awk, /usr/xpg6/bin/awk, or nawk instead of awk.
This User Gave Thanks to Don Cragun For This Post:
# 18  
Old 08-26-2013
@Don: see post #7
# 19  
Old 08-26-2013
Would sed be an option? Try
sed -r 's/^(.{16}) /\1C/' file

This User Gave Thanks to RudiC For This Post:
# 20  
Old 08-28-2013
thejitha@ubuntu:~$ awk --version
awk: not an option: --version

# 21  
Old 08-28-2013
locate awk

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