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# 1  
Old 08-08-2013
awk command issue

Hi All,

I have one file with below content

Code:
 
 Post1:uri
Post2:urieop
Post3:urtei

I am trying to read each word seprated by delimiter with below command

Code:
 
Value1=$(awk -F":" '{print $1}' $HSFILE)
Value2=$(awk -F":" '{print $2}' $HSFILE)
echo $Value1
echo $Value2

It is giving output to me

Code:
 
Post1
Post2
Post3
 
uri
urieop
urtei


But I want in

Code:
 
Post1
uri
Post2
urieop
Post3
urtei


Could you please suggest?
# 2  
Old 08-08-2013
Try:
Code:
awk '1' RS=':'  infile

# 3  
Old 08-08-2013
I believe below will get you what you're looking for.

Code:
d@AirBox:~$ v1=($(awk -F\: '{print $1}' file))
d@AirBox:~$ v2=($(awk -F\: '{print $2}' file))
d@AirBox:~$ for ((i=0 ; i < ${#v1[@]} ; i++));do printf "${v1[$i]}\n${v2[$i]}\n";done
Post1
uri
Post2
urieop
Post3
urtei

In shell, because insomnia.

Code:
d@AirBox:~$ while read line;do  printf "${line%%:*}\n${line##*:}\n";done < file
Post1
uri
Post2
urieop
Post3
urtei
d@AirBox:~$


Last edited by DeCoTwc; 08-08-2013 at 04:48 AM.. Reason: insomnia
This User Gave Thanks to DeCoTwc For This Post:
# 4  
Old 08-08-2013
Code:
$ tr ':' '\n' < file
Post1
uri
Post2
urieop
Post3
urtei

This User Gave Thanks to anbu23 For This Post:
# 5  
Old 08-08-2013
Hello,

Could you please try the following code please.
Let us say test_file have the data as per your request.


Code:
$ cat test_file.ksh
value1=`awk -F: '{print$2}' test_file`
value2=`awk -F: '{print$1}' test_file`
k=0
l=0
set -A array_value1 ${value1}
set -A array_value2 ${value2}
for i in ${array_value1[@]}
do
l=0
for j in ${array_value2[@]}
do
if [[ $k -eq $l ]]
then
echo $j
echo $i
fi
let "l = l +1 "
done
let "k =k +1 "
done



Then Output should be as follows.

Code:
$ ksh test_file.ksh
Post1
uri
Post2
urieop
Post3
urtei



Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
# 6  
Old 08-08-2013
thanks Guys, Evryone's code is working

I am going to use DeCoTwc code.

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