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# 8  
Old 07-17-2013
Thanks, but what you can advise for me in my case.
Stas.

---------- Post updated at 01:53 AM ---------- Previous update was at 01:34 AM ----------

Hi rajamadhavan.,
Perl commands not help me, sorry.
Thanks Stas.
# 9  
Old 07-17-2013
try something like this.. Here i asuumed DATAFILE as pattern after your last , removal

Code:
 
sed -n '/^DATAFILE/{x;s/,//;x;};1h;1!{x;p;};${x;p;}' filename

# 10  
Old 07-17-2013
Please edit your code and wrap it in [code] tags! (See the top of the WIKI editor.)
Based on your first sample (corrected by Scott), here is something that works with the indention:
Code:
awk '{i=index($0,")")} i>0 {s=$0; getline; j=index($0,$1); if (j<i) sub(", *$","",s); print s} {print}' file

The sub() strips the comma at the end if the next line has got less indention.
# 11  
Old 07-17-2013
Thanks vidyadhar85.,
You sed command is work perfect, can you only explain me what some of brackets are mean ......
Code:
sed -n '/^DATAFILE/{x;s/,//;x;};1h;1!{x;p;};${x;p;}'

Thanks Stas.
Last edited by Scott; 07-17-2013 at 09:30 AM.. Reason: Code tags
# 12  
Old 07-17-2013
Quote:
Originally Posted by beckss
Thanks vidyadhar85.,
You sed command is work perfect, can you only explain me what some of brackets are mean ......


sed -n '/^DATAFILE/{x;s/,//;x;};1h;1!{x;p;};${x;p;}'


Thanks Stas.
Glad it worked out for you Smilie

here on finding DATAFILE ^ indicates starting from.. exchange the pattern and hold space then replace the , and again do the same
1h indicates copy of pattern space to hold space so that when pattern found we have previous line in hold space.
1!{x;p;};${x;p;} these are to avoid blank lines
# 13  
Old 07-17-2013
Once you have understood this, you can simplify to
Code:
sed '/^DATAFILE/{x;s/, *$//;x;};1h;1d;x;$p;$x'

Still it only works with GNU sed.
The Unix sed seem to have a problem with the { }. (That's why I prefer awk.)
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