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awk command format ?

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# 1  
Old 11-14-2005
awk command format ?
Can some body tell me the meaning of '$1=$1' in the following syntax.

nawk -v RS='' -v OFS=',' '$1=$1' myFile.txt


Thanks,
Mahesh Smilie
# 2  
Old 05-05-2009
Need clarification
Hi,

Could anybody explain me the peice of code below as well:
filecount()
{
[ -e "$1" ] && numfiles=$# || numfiles=0
}
# 3  
Old 05-05-2009
Quote:
Originally Posted by rjanardhan83
Hi,

Could anybody explain me the peice of code below as well:
filecount()
{
[ -e "$1" ] && numfiles=$# || numfiles=0
}
If the pass filename exists then set numfiles to the no of arguments passed
if not, the set numfiles to 0.

cheers,
Devaraj Takhellambam
# 4  
Old 05-06-2009
Quote:
Originally Posted by devtakh
If the pass filename exists then set numfiles to the no of arguments passed
if not, the set numfiles to 0.

cheers,
Devaraj Takhellambam


Hi,

Thank you so much for the help.Could you also please elaborate what is meant by [ -e "$1"]...

rgrds,
janardhan
# 5  
Old 05-06-2009
Power This should help your cause
Here, [ -e var1 ] is used here to check for the existence of that variable
( var1), In your case its,$1 , which signifies the first argument bring passed to the script.


I hope this suffices the question..Smilie

Regards,
Last edited by abhisek.says; 05-06-2009 at 09:32 AM.. Reason: Spelling change
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