Execute command with loop


 
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# 8  
Old 07-07-2013
If you are writing for /bin/sh then it would be best to use a while loop:
Code:
i=0
while [ $((i+=1)) -le 1000 ]
do

If you can use bash, then you could use:
Code:
for i in {1..1000}
do

But I am guessing 20130613 is a date, right? You would need to take that into acount when incrementing $c
This User Gave Thanks to Scrutinizer For This Post:
# 9  
Old 07-07-2013
I Used Below code in which "for i in `seq 1 $max`" worked for me

Thanks for the Help Smilie

Code:
#!/bin/sh
#
#Script to test for loop
#
#
if [ $# -eq 0 ]
then
echo "Error - Number missing form command line argument"
echo "Syntax : $0 number"
echo " Use to print multiplication table for given number"
exit 1
fi
a=$1
max=$2
c=$3
for i in `seq 1 $max`
do
parti=parti
#echo "ALTER TABLE seats  ADD PARTITION ( PARTITION $c$parti VALUES less than (DAY( `expr $a \+ $i`)));"
#s=expr $a \+ $i
mysql -u root -p'root' test -e "ALTER TABLE seats  ADD PARTITION ( PARTITION $c$parti VALUES less than (`expr $a \+ $i`));"
c=`expr $c \+ 1`
done

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