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Help me with daily monitoring script

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Top Forums Shell Programming and Scripting Help me with daily monitoring script
# 29  
Old 07-23-2013
Code:
find /usr/IBM/FileNet/BulkUploaderScript/$i/Log/SuccessLog \
   \( -newer range_start -a \! -newer range_end \) \
   | while read file
do
  
 lines=`wc -l "$file"`
# details=`ls -l "$file" | read w x y z d1 d2 d3 rest`--->commented ,in this intailzing is problem 
 details=`ls -l "$file"`
 echo $details
 echo "File $file has $lines lines and a date of $d1 $d2 $d3" 
 echo $file>>$LOGFILE
done

OUTPUT:
-rwxrwxrwx 1 ce_admin ce_admin 718 Jun 7 15:32 /usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv

File /usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv has 4 /usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv lines and a date of


I need only last modified date of the file not access time .
And i am getting number of lines with filename but i need only number.
Any alternative or any modifications
# 30  
Old 07-23-2013
Smilie Okay, I've spotted my first mistake. The output from ls -l "$file" has, of course, five colums to skip (permissions, links, owner, group & bytes) and what I suggested only has four dummy placeholders (w, x, y & z) Smilie

Lets try adding dummy placeholder v to that:-
Code:
find /usr/IBM/FileNet/BulkUploaderScript/$i/Log/SuccessLog \
   \( -newer range_start -a \! -newer range_end \) \
   | while read file
do
   lines=`wc -l "$file"`
   details=`ls -l "$file" | read v w x y z d1 d2 d3 rest`
   echo "File \"$file\" has \"$lines\" lines and a date of \"$d1\" \"$d2\" \"$d3\""
   echo $file>>$LOGFILE
done

I've added in a lot of escaped quotes \" so that the output clearly defines each variable to see if I've missed something else.

Can you have a go and post the output in code tags - it makes it easier to read.


Thanks Smilie, and apologies Smilie
Robin
# 31  
Old 07-25-2013
Still facing Issue that d1 ,d2,d3 not printing
Output::
Quote:
File "/usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLo gHIPAACERTS7-6-2013 15-32-18.csv" has"4/usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv" lines and a date of "" "" ""
# 32  
Old 07-25-2013
Maybe we shoudl drop the details= bit:-
Code:
find /usr/IBM/FileNet/BulkUploaderScript/$i/Log/SuccessLog \
   \( -newer range_start -a \! -newer range_end \) \
   | while read file
do
   lines=`wc -l "$file"`
   ls -l "$file" | read v w x y z d1 d2 d3 rest
   echo "File \"$file\" has \"$lines\" lines and a date of \"$d1\" \"$d2\" \"$d3\""
   echo $file>>$LOGFILE
done

A schoolboy error of mine Smilie that makes these values would only be set within the sub-shell running the ls -l | read......


Can you actually copy & paste all the code block in, as you output didn't quite tally.

Does that help?



Robin
# 33  
Old 07-26-2013
Code:
find /usr/IBM/FileNet/BulkUploaderScript/$i/Log/SuccessLog \
   \( -newer range_start -a \! -newer range_end \) \
   | while read file
do
  
  lines=`wc -l "$file"`
   ls -l "$file" | read v w x y z d1 d2 d3 rest
   echo "File \"$file\" has \"$lines\" lines and a date of \"$d1\" \"$d2\" \"$d3\""
   echo $file>>$LOGFILE
done

Quote:
File "/usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv" has " 4 /usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv" lines and a date of "" "" ""
Variable "lines" reading filename also with the number of lines in the file .Majorly problem is d1,d2,d3 is not showing any output .What is the solution we have now .

Thanks
Raghavendra
# 34  
Old 07-26-2013
Another variation to see where we're going:-
Code:
find /usr/IBM/FileNet/BulkUploaderScript/$i/Log/SuccessLog \
   \( -newer range_start -a \! -newer range_end \) \
   | while read file
do
  lines=`grep -c "" "$file"`
   ls -l "$file" | read v w x y z d1 d2 d3 rest
   echo "File \"$file\" has \"$lines\" lines and a date of \"$d1\" \"$d2\" \"$d3\""
   echo $file>>$LOGFILE
done

That should sort the counting. Testing here, the d1, d2 & d3 works fine for me:-
Code:
$ file=.profile
$ lines=`grep -c "" "$file"`
$ ls -l "$file" | read v w x y z d1 d2 d3 rest
$ echo "File \"$file\" has \"$lines\" lines and a date of \"$d1\" \"$d2\" \"$d3\""
File ".profile" has "12" lines and a date of "02" "May" "2012"
$

It would suggest that your code might have ls -1 | read .... instead of ls -l | read .... To clarify, you may have a number one where it needs a lower case L.


Can you have another go?


Robin
# 35  
Old 07-26-2013
ksh reads the last part of the pipe in the current shell:
Code:
ls -l "$file" | read v w x y z d1 d2 d3 rest

sh,bash need a work-around:
Code:
read v w x y z d1 d2 d3 rest << _EOT
`ls -l "$file"`
_EOT

Or
Code:
set -- `ls -l "$file"`
d1=$6; d2=$7; d3=$8
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