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Help me with daily monitoring script

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# 22  
Old 07-12-2013
Code:
find /usr/IBM/FileNet/BulkUploaderScript/$i/Log/SuccessLog \
   \( -newer range_start -a \! -newer range_end \) \
   | while read file
do
    lines=`wc -l "$file"`---->i need number of lines in the file  but i am getting filename also  as shown below in the output
   ls -l "$file" | read w x y z d1 d2 d3 rest--> it is not intializing variables but how to  do that , i need basically lastmodification time rather than all infromation 
echo "File $file has $lines lines and a date of $d1 $d2 $d3" 
  done

OUPUT:

File /usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv has 4
/usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv lines and a date of

Please give a sloution .
# 23  
Old 07-12-2013
Quote:
Originally Posted by rbatte1
Can we see output from ls -l too. That's a lower case L flag.


Regards,
Robin
# 24  
Old 07-15-2013
I am not able to see any output for that paticular ls-l
# 25  
Old 07-22-2013
ls-l is not working , i mean it is not showing any output . please go through the above code in previous posts , if we do a minor change code will work . Please look into it and help
# 26  
Old 07-22-2013
Do you have a space between ls & -l?

When you say no output, do you mean absolutely nothing at all except that the prompt returns? You should get something, a total line, an error message, something surely.



Robin
# 27  
Old 07-22-2013
Code:
find /usr/IBM/FileNet/BulkUploaderScript/$i/Log/SuccessLog \
   \( -newer range_start -a \! -newer range_end \) \
   | while read file
do
  
  lines=`wc -l "$file"`-----
---->i need number of lines in the file  but i am getting filename also  as shown below in the output     
`ls -l "$file" | read w x y z d1 d2 d3 rest`-----
it is not intializing variables but how to  do that , i need basically lastmodification time ratherecho "File $file has $lines lines and a date of $d1 $d2 $d3" 
    echo $file>>$LOGFILE
done

OUPUT:
for all the lines above written

File /usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv has 4
/usr/IBM/FileNet/BulkUploaderScript/LogsFolder/Log/SuccessLog/CSVSuccessLogHIPAACERTS7-6-2013 15-32-18.csv lines and a date of



please suggest any alternative or proper solution
# 28  
Old 07-22-2013
So, can we see the output of just ls -l on it's own in the correct directory. No further scripting, just the plain ls -l thanks.


Thanks,
Robin
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