Shell Programming and Scripting

Hi all,

In our webserver customer wants to see the latest 10 files arrived. So the names are hardcoded in webpage like :

filename_01.txt
filename_02.txt
....
....
filename_10.txt

where the filename_01.txt is the latest one (typically the output of ls -1t) in the /../webpage directory.

I will have to schedule a daemon/cron job that picks new incoming files from directory /../land (both are in same server) - filename are standard - say new_file_ddmmyy and move to /../webpage directory.

Now the latest moved file will be renamed to filename_01.txt.
the old filename_01.txt will be renamed to filename_02.txt
and so on.

this will be a dynamic script.

Any idea/algorithm/logic/script will help me a lot.

Thanks in advance.

~
sabya

You don't say which shell you are using. This is bash...

Code:

for (( x=9 ; x>0 ; x-- ))
do
   y=$(printf "%02d" $x)
   z=$(printf "%02d" $((x+1)))
   echo mv filename_$y.txt filename_$z.txt
done

...remove the echo if it does what you want.

On second thoughts, since the number of files is hard-coded why not just copy and paste the output from this script...

Code:

mv filename_09.txt filename_10.txt
mv filename_08.txt filename_09.txt
mv filename_07.txt filename_08.txt
mv filename_06.txt filename_07.txt
mv filename_05.txt filename_06.txt
mv filename_04.txt filename_05.txt
mv filename_03.txt filename_04.txt
mv filename_02.txt filename_03.txt
mv filename_01.txt filename_02.txt

I am using ksh.
thanks a lot. I was planning to go from top to bottm and messing things up.