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To read specific line from a file

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# 1  
Old 03-10-2013
To read specific line from a file
Hi,

I have a ldif file like below:
Code:
version: 1

dn: cn=Test Group,ou=Applications,dc=xyz,dc=com
objectClass: groupOfUniqueNames
objectClass: top
cn: Test Group
uniqueMember: uid=abc,ou=People,o=xyz,o=Corporate,dc=xyz,dc=com

dn: cn=Test Sub Group,cn=Test Group,ou=Applications,dc=xyz,dc=com
objectClass: groupOfUniqueNames
objectClass: top
cn: Test Sub Group
uniqueMember: uid=def,ou=People,o=xyz,o=Corporate,dc=xyz,dc=com
uniqueMember: uid=fgh,ou=People,o=xyz,o=Corporate,dc=xyz,dc=com


I need to output from above file as :
Code:
uid=abc,ou=People,o=xyz,o=Corporate,dc=xyz,dc=com
uid=def,ou=People,o=xyz,o=Corporate,dc=xyz,dc=com
uid=fgh,ou=People,o=xyz,o=Corporate,dc=xyz,dc=com

Please help.
# 2  
Old 03-10-2013
grep "uid=" filename | awk '{print $2}'
# 3  
Old 03-10-2013
Code:
awk '$2~"uid" {print $2}' file

Or
Code:
sed -n "s/[^ ]* uid/uid/p" file

# 4  
Old 03-10-2013
Quote:
Originally Posted by PikK45
grep "uid=" filename | awk '{print $2}'
This is Useless Use of grep | awk

Another approach using GNU grep:
Code:
grep -o "uid.*" file

This User Gave Thanks to Yoda For This Post:
PikK45
# 5  
Old 03-11-2013
Thanks a lot ,

All worked.
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