Scrutinizer, thanks ,awk code works great thanks for making the awk version of factorial, seems there is a limitation of 171th calculation. But it is good to have the code .Thanks,
- For the first unix command based code with sed & bc:
Out of curiosity I tried Jotne's remark for n=1000 value and it worked like a charm .
Also wondered when I put it n=2000, we know factorial of 2000 is going to be huge, and this too worked on Suse 11.2 VM perfectly. It was kind of grabled the display at the 19xx as it was processing so quickly.
---------- Post updated at 06:08 PM ---------- Previous update was at 05:56 PM ----------
All, Out of curiosity I increased factorial value , n=2000 and it worked to:
Code:
n=2000;for i in `seq $n`;do printf "`seq $i|xargs|sed 's/ /*/g'`= ";echo "`seq $i|xargs|sed 's/ /*/g'`"| bc;done
Showing factorial of 2000 below :
on Linux Suse 11.2 VM , shell = /bin/bash
Code:
GNU bash, version 3.2.51(1)-release (x86_64-suse-linux-gnu)
# n=20;for i in `seq $n`;do printf "`seq $i|xargs|sed 's/ /*/g'`= ";echo "`seq $i|xargs|sed 's/ /*/g'`"| bc;done
...<snip>...
# n=20;for i in `seq $n -1 1`;do printf "`seq $i|xargs|sed 's/ /*/g'`= ";echo "`seq $i|xargs|sed 's/ /*/g'`"| bc;done
#
Thank you for sharing, rveri. I took the liberty of further distilling your contribution. The following use a subset of the tools used by your originals.
Code:
Distilled ascending:
n=20; for i in $(seq $n); do s=$(seq -s\* $i); printf "\"$s= \"\n$s\n" | bc; done
Distilled descending:
n=20; for i in $(seq $n -1 1); do s=$(seq -s\* $i); printf "\"$s= \"\n$s\n" | bc; done
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02-06-2013
