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How to extract hostname from file using awk?

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# 8  
Old 02-05-2013
Code:
awk -F'[]#]' '{print $2}' file

# 9  
Old 02-05-2013
Hi

not getting output as desired.

root@blr-svr-oclan-01 # awk -F'[]#]' '{print $2}' x


output

HTML Code:
local]pun-ras-bng-mhs-01#cont bsnl.in
local]enk-ras-bng-cse-01#cont bsnl.in
root@blr-svr-oclan-01 #
Required output will be

HTML Code:
HOSTNAME
pun-ras-bng-mhs-01
enk-ras-bng-cse-01
# 10  
Old 02-05-2013
Quote:
Originally Posted by ./hari.sh
If you are in Solaris, use nawk instead of awk
# 11  
Old 02-05-2013
Hi

if iam using nawk. no output is coming

Code:
root@blr-svr-oclan-01 # nawk -F'[]#]' '{print $2}' x

Last edited by Scrutinizer; 02-05-2013 at 09:05 AM..
# 12  
Old 02-05-2013
On Solaris use /usr/xpg4/bin/awk rather than awk or nawk
This User Gave Thanks to Scrutinizer For This Post:
surender reddy
# 13  
Old 02-05-2013
Hi,

now code is working fine.

Code:
root@blr-svr-oclan-01 # /usr/xpg4/bin/awk -F'[]#]' '{print $2}' x
pun-ras-bng-mhs-01
enk-ras-bng-cse-01
root@blr-svr-oclan-01 #

tnx
Last edited by Scrutinizer; 02-05-2013 at 09:27 AM.. Reason: code tags
# 14  
Old 02-05-2013
there are many ways to achieve desired target
Code:
<filename cut -d] -f2 | cut -d'#' -f1

awk -F'[]#]' '{ print $2 }' filename

sed 's/.*]\|#.*//g' filename

perl -pe 's/.*\]|#.*//g' filename
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