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Shell Programming and Scripting

Replacing last spacebar

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# 1  
Old 01-05-2013
Replacing last spacebar
I need to use bash to replace the last spacebar character for each line in a file so that e.g.:

Code:
f d e 3 5

becomes

Code:
f d e 3/5

Moderator's Comments:
Mod Comment
Please use code tags when posting data and code samples!
Last edited by vgersh99; 01-05-2013 at 01:26 PM.. Reason: code tags, please!
# 2  
Old 01-05-2013
Code:
echo 'f d e 3 5' | sed 's#\(.*\) #\1/#'

# 3  
Old 01-05-2013
Code:
line="f d e 3 5"
echo ${line/% ?/\/}${line: -1}

Note: This will not work for variable length string. So using solution provided by vgersh99 is the best approach.
# 4  
Old 01-05-2013
With awk

Code:
echo "f d e 3 5" | awk '{$0=gensub(/ /,"/",(NF-1))};1'
f d e 3/5

# 5  
Old 01-05-2013
Quote:
Originally Posted by Jotne
With awk

Code:
echo "f d e 3 5" | awk '{$0=gensub(/ /,"/",(NF-1))};1'
f d e 3/5

only with gawk
# 6  
Old 01-05-2013
Hmm, I see that my awk points to gawk
So it will at least work in Ubuntu
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