I am betting this is a very simple thing, but I admit i don't know the proper terms to search it out correctly.
I am self-learning at work.
I've come on a section of code in a script:
What I can't figure out(or search out) is what the arguments "5 2 2>&1" are doing??
I thought it was setting 2 '5 byte messages' with a time to live of 2...something.
But I can not find any data to support that or otherwise explain what's going on here.
Check man ping on that system (I'm guessing it is Solaris) to get explanation of 5 2. 2>&1 is a redirection technique, allowing to "merge" standard error messages into standard output stream.
Hi friends! I'm learning UNIX and I have a small question. Working with Shell, i put the name of one executable (in c language) + one number and it says this:
$ gcc misterioso_4.c
$ ./misterioso_4 6
got: ,
I can not find an answer in the manual because I havent applied any variable.... (5 Replies)
Can someone do me a favour and explain the following for me:
((r=$RANDOM%$n+1))
I know what $RANDOM does but what is % sign and what does it do with %$n+1? (2 Replies)
hi all i have an example i want one help me to understand cause i tried to test it but almost fail and i don't know how can i solve this problem " the main idea to read from two files and replace something from one to another " but i don't understand why it fail all time
$ cat main.txt... (4 Replies)
if
then
echo "Syntax: $0 <sid> <COLD/HOT> <DEST>"
exit
fi
if --------------what does this mean???
echo "Syntax: $0 <sid> <COLD/HOT> <DEST>"---pls explain this as well (2 Replies)
this is the mksys b script....
can anyone explain .. what # and 1 in if condition
this is the first line of the script... it is not from middle of the script....
if
then
echo "Not enough parameters, need a client name for mksysb"
Usage="Usage: $0 <client name>"
... (2 Replies)
zsh 4.3.4% cat file
ACFCFACCACARCSHFARCVJVASTVAJFTVAJVGHBAJ
zsh 4.3.4% cat file1
A
C
F
R
zsh 4.3.4% <file1 while read;do printf "%s=%d\n" "$REPLY" "${#$(<file)//}";done
A=9
C=7
F=4
R=2
That was the previous post.
But , can anybody can explain me in detail about this line
zsh... (2 Replies)