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awk fails when using variable

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# 1  
Old 12-13-2012
awk fails when using variable
This works when I try to execute normally :

Code:
echo | format | nawk '/pci@1f,4000/{print x}; {x=$0 }'

But fails when define a variable and put it in a file:

Code:
cat test
c=pci@1f,4000
echo | format | nawk "/$c/{print x}; {x=$0 }"

./test
nawk: syntax error at source line 1
 context is
        /pci@1f,4000/{print x}; >>>  {x=. <<< /test }
nawk: illegal statement at source line 1

Any suggestions.
Last edited by Scrutinizer; 12-13-2012 at 01:03 AM.. Reason: code tags
# 2  
Old 12-13-2012
Change as below and try..
Code:
$ c="pci@1f,4000"
$ nawk '/c/{print x}; {x=$0 }'

# 3  
Old 12-13-2012
That doesn't work either.

I thought " " should be used instead of ' ' because when using variables double quotes should be used. Btw.

Code:
c=pci@1f,4000
echo | format | nawk "/$c/ {print}"

This works perfectly fine.
And I am using Solaris. "grep -B" isn't working. Any other code?
Last edited by Scrutinizer; 12-13-2012 at 04:23 AM.. Reason: icode -> code tags
# 4  
Old 12-13-2012
In the first sample you use single quotes, in the second you use double quotes. Because of these $0 is processed as a shell variable, so you would need to escape that $-sign (x=\$0). Or try:
Code:
c=pci@1f,4000
echo | format | nawk -v c="$c" '$0~c{print x} {x=$0 }'

which should work as long as c does not contain special (extended regular expression) characters, in which case they would need to be escaped...


--
Quote:
Originally Posted by michaelrozar17
Change as below and try..
Code:
$ c="pci@1f,4000"
$ nawk '/c/{print x}; {x=$0 }'

There is no need for the double quotes here. /c/ matches the character "c"
Last edited by Scrutinizer; 12-13-2012 at 01:54 AM..
These 2 Users Gave Thanks to Scrutinizer For This Post:
aksijain michaelrozar17
# 5  
Old 12-13-2012
Thanks for that code. It worked.

Can you please elaborate where exactly I was going wrong. Thanks.
# 6  
Old 12-13-2012
Hi aksijain, I wrote something in my post, does that help?
# 7  
Old 12-13-2012
@Scrutinizer
Since both the variable and its value contains character c, i was getting the correct result while testing.However i must have verified again the command.
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