awk: process a part of string, leaving others unchanged

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09-26-2012

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Quote:

Originally Posted by elixir_sinari

Something simpler with awk:

Code:

awk '{split($1,a,".");print a[4],a[3],a[2],a[1] " " $2}' OFS='.' file

Hi elixir,

In my above script i am considering if there are any more occurrence of the fields..
like..

Code:

$cat file
11.22.33.44.in-addr.arpa xxx.yyy
22.33.44.55.in-addr.arpa xxx.yyy.zzz
100.5.10.20.in-addr.arpa a.b.c.d 100.5.10.20.in-addr.arpa a.b.c.d

Is there any simpler ways to handle printf

Last edited by pamu; 09-26-2012 at 10:34 AM..

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