Shell Programming and Scripting

I'm using a directory naming convention to organize files as exemplified here:

2012/Aug/week-20-Aug/23-Thu/tuv.txt
2012/Aug/week-27-Aug/30-Thu/abc.txt
2012/Sep/week-27-Aug/01-Sat/def.txt
2012/Sep/week-03-Sep/07-Fri/xyz.txt

How do I write a command that will list the file names abc.txt and def.txt because they are both in same week?

I cannot assume the file system dates for modification or creation of the file matches the directory they are stored in.

Thanks
Siegfried

Use find(1):

Code:

find 2012/Aug/week-27-Aug -type f

Thanks but that won't find the file 2012/Sep/week-27-Aug/01-Sat/def.txt.

How can I start searching from 2012 and find both files def.txt and abc.txt and not find tuv.txt or xyz.txt?

What's your system?

On Linux I might do this:

Code:

# Search inside all months for weeks
find 2012 -maxdepth 2 -mindepth 2 -type d | while read WEEK
do
        # Glob all files for that week
        set -- "$WEEK"/*/*.txt

        # Print if more than one is found for that week
        [ "$#" -gt 1 ] && echo "$@"
done

Code:

find 2012/*/week-27-* -type f

Regards,
Alister