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delimiting using sed command

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# 8  
Old 09-17-2012
Quote:
Originally Posted by mosies
is there a difference between /bin/awk (which is the default) and /usr/xpg4/bin/awk ??
Check this thread What is the difference between xpg4/bin and usr/bin?.
# 9  
Old 09-17-2012
A similar way in sed - select lines starting with "FAN" and print the last word, minus the surrounding brackets, would be:

Code:
sed -n '/^FAN/ {; s/^FAN[<spc><tab>]*//; s/\]//; s/\[//;p'

Replace "<spc>" and "<tab>" with literal spaces/tabs.

I hope this helps.

bakunin
# 10  
Old 09-17-2012
Code:
sed -n '/^FAN/ s/.*\[\([^][]*\)\]$/\1/p' <file

--
Bye
This User Gave Thanks to Lem For This Post:
mosies
# 11  
Old 09-17-2012
Another approach with sed:
Code:
sed -n '/^FAN/s/.*\[\(.*\)\]/\1/p' file

This User Gave Thanks to Franklin52 For This Post:
mosies
# 12  
Old 09-17-2012
Quote:
Originally Posted by elixir_sinari
Assuming that in the line containing FAN, only the Status column has square brackets:
Code:
FAN_STAT=`awk -F'[][]' '/FAN/{print $2}' prt.log`

Hi elixir,

Can i check with you why is it you did awk -F '[][]' ?
I know -F is the field separator, but why the square brackets twice...?

Many thanks!
# 13  
Old 09-18-2012
Quote:
Originally Posted by mosies
Hi elixir,

Can i check with you why is it you did awk -F '[][]' ?
I know -F is the field separator, but why the square brackets twice...?

Many thanks!
That means 2 field separators an open [ and a closed ] square bracket.
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