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Creating array from file

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# 8  
Old 09-10-2012
You probbly have more than 1 space between each field, try using awk instead of cut:

Code:
arr=( $(awk '{ print $4}'  out.txt)
echo ${arr[@]}

This User Gave Thanks to Chubler_XL For This Post:
Lord Spectre
# 9  
Old 09-10-2012
Quote:
Originally Posted by Lord Spectre
Yes bash, but the command doesn't work for me :-(

Code:
#!/bin/bash
arr=( $(cut -d" " -f4 out.txt) )  
echo ${arr[@]}

result empty array:
Of course: if you load the array in a subshell (scripts are run in subshells), how can you have it in the parent shell?
------- EDIT ------------------------------
Sorry, I misread your message: I thought you were running echo outside the script.
--
Bye
# 10  
Old 09-10-2012
Quote:
Originally Posted by Chubler_XL
You probbly have more than 1 space between each field, try using awk instead of cut:

Code:
arr=( $(awk '{ print $4}'  out.txt)
echo ${arr[@]}

Oh YES!!! More space between fields!!! Smilie
Your command works ok, except for the fact you've missed one ')' Smilie

Code:
arr=( $(awk '{ print $4}'  out.txt) )
echo ${arr[@]}

Thanks all for partecipating! Apreciated! Smilie

---------- Post updated at 04:04 PM ---------- Previous update was at 03:12 PM ----------

Guys sorry, whitout opening a new thread, is it possible to put into an array the whole line?

Code:
1234567890 1 1 9876[9876=1]
7634567890 1 1 3456[3456=1]
8934567890 1 4 0123[0123=1];1234[4567=3]
5534567890 1 1 0001[0101=1]
7834567890 1 1 3256[3256=1]
4534567890 1 1 7560[7560=1]
1334567890 1 1 900[0900=1]
0034567890 1 2 9899[9899=2]

So the array will be:
Code:
arr[0]="1234567890 1 1 9876[9876=1]"
arr[1]="7634567890 1 1 3456[3456=1]"
arr[2]="8934567890 1 4 0123[0123=1];1234[4567=3]"
....
....

Then later I'll take the 4th value and the other one to post-process them....
# 11  
Old 09-10-2012
To put into an array the whole lines of a file:
Code:
mapfile -t myarray <file

help mapfile for details.
--
Bye
# 12  
Old 09-10-2012
Note mapfile requires bash 4 is you are still on 3 you may need to use cat:

Code:
OLDIFS=$IFS
IFS=$'\n'
arr=( $(cat out.txt) )
IFS=$OLDIFS

This User Gave Thanks to Chubler_XL For This Post:
Lord Spectre
# 13  
Old 09-10-2012
Quote:
Originally Posted by Chubler_XL
Code:
IFS=$'\n'
arr=( $(cat out.txt) )

It may not be an issue for this data set, but, just in case, I'll mention that this approach deletes newlines since contiguous IFS whitespace is treated as a single delimiter.

If the situation requires preserving lines (including newlines) exactly as they appear in the text file, the following will do it:
Code:
while IFS= read -r line; do
    arr[${#arr[@]}]=$line;
done

Regards,
Alister
This User Gave Thanks to alister For This Post:
Lord Spectre
# 14  
Old 09-11-2012
Thanks all for partecipating, I'll keep all your suggestion for future use! Smilie

For now, I'll create 4 array for each row in the output file. This will simplify my post-processing!

Smilie

Just a question, if I can, mapfile is not present in my bash. This because probably I don't have bash v4.
How can I upgrade to bash v4 ??
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