Of course: if you load the array in a subshell (scripts are run in subshells), how can you have it in the parent shell?
------- EDIT ------------------------------
Sorry, I misread your message: I thought you were running echo outside the script.
--
Bye
Hi,
Is it possible to create a dynamic array in shell script. I am trying to get the list of logfiles that created that day and put it in a dynamic array. I am not sure about it. help me
New to scripting
Gundu (3 Replies)
Hi all,
i am quite fimiliar with shell scripting but i wouldn't regard myself as a semi professional at it.
I am trying to create an array variable to read in 4 lines from a file using head and tail command in a pipeline and store each line into each array. I have done the scripting in unix... (2 Replies)
i want to create an array
the array elements are populated depending upon the number of entries present in a data file
The data file is created dynamically
how to achieve the same
thanks (1 Reply)
I am facing a strange error while creating posix threads:
Given below are two snippets of code, the first one works whereas the second one gives a garbage value in the output.
Snippet 1
This works:
--------------
int *threadids;
threadids = (int *) malloc (num_threads * sizeof(int));
... (4 Replies)
I am wondering how I can save the file names (stored in $file or $fnames) in array which I can access with an index.
alias MATH 'set \!:1 = `echo "\!:3-$" | bc -l`'
set narg = $#argv
while ($iarg < $narg)
MATH iarg = $iarg + 1
set arg = $argv
set opt = ` echo $arg | awk... (1 Reply)
I have an interesting requirement. I have declaried an array like :-
arr=`find . ! -name "." | xargs -I {} echo {} | cut -c 2-${#}`
Then i will try to access the array elements like :-
i=0
for i in ${arr}; do
Here comes the confusions, the array elements are basically dir and files stored... (2 Replies)
Hi gurus,
I need to create arrays from variables, via a loop.
The issue I have is with the array name creation. How do I use a variable to define an array?
I want to do something like
declare -a $H
where $H is my loop variable.
I then need to add items to each array I've created,... (3 Replies)
I am having trouble creating an array, I've tried everything google gives me but it won't work, and it seems as though it should. Using Ubunto 12.04 and bash.
#!/bin/bash
ARRAY=one two three
echo ${ARRAY}When I do this I receive the error
: two: not found
and
: Bad substitution
When I... (3 Replies)
Hi Guys,
I am writting a c shell script where I have to parse an input argument with options that could be an array. So far I have achieved where I could parse a single argument with option but failed when I try to create an array with the options. For example:
This is on terminal window:... (2 Replies)
Discussion started by: dixits
2 Replies
LEARN ABOUT PHP
pg_fetch_all
PG_FETCH_ALL(3)PG_FETCH_ALL(3)pg_fetch_all - Fetches all rows from a result as an arraySYNOPSIS
array pg_fetch_all (resource $result)
DESCRIPTION pg_fetch_all(3) returns an array that contains all rows (records) in the result resource.
Note
This function sets NULL fields to the PHP NULL value.
PARAMETERS
o $result
- PostgreSQL query result resource, returned by pg_query(3), pg_query_params(3) or pg_execute(3) (among others).
RETURN VALUES
An array with all rows in the result. Each row is an array of field values indexed by field name.
FALSE is returned if there are no rows in the result, or on any other error.
EXAMPLES
Example #1
PostgreSQL fetch all
<?php
$conn = pg_pconnect("dbname=publisher");
if (!$conn) {
echo "An error occurred.
";
exit;
}
$result = pg_query($conn, "SELECT * FROM authors");
if (!$result) {
echo "An error occurred.
";
exit;
}
$arr = pg_fetch_all($result);
print_r($arr);
?>
The above example will output something similar to:
Array
(
[0] => Array
(
[id] => 1
[name] => Fred
)
[1] => Array
(
[id] => 2
[name] => Bob
)
)
SEE ALSO pg_fetch_row(3), pg_fetch_array(3), pg_fetch_object(3), pg_fetch_result(3).
PHP Documentation Group PG_FETCH_ALL(3)