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passing argument from one function to another

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# 36  
Old 09-03-2012
What error's you are getting....??

For file presence checking i've done one mistake...

Try with this..

Code:
Initialize () {
    echo  > $FileName
    { rm $CARD; sed -e "s/data[a-zA-Z0-9]/data1/g" > $CARD; } < $CARD
    { rm $CondorJob; sed -e "s/temp[a-zA-Z0-9]/temp0/g" > $CondorJob; } < $CondorJob
    echo "Initialize  the Values"
}

CopyFilesInfo() {
    for FileNameIndx in "${PATHNAME[@]}"
    do
    if [[ ! -e "dest_path/$FileNameIndx" ]] 
    then
    ls -ltr "$FileNameIndx" | grep root | awk '{print string path $9}' string="$CONSTANT" path="$FileNameIndx"  >> "$FileName"
    echo "$FileNameIndx is copied" 
    else
    echo "Check the FileName in ${PATHNAME[@]}"
    fi
    done
}

Last edited by pamu; 09-03-2012 at 06:30 AM.. Reason: Corrected code...
# 37  
Old 09-03-2012
Thanks for the corrections.
I am not getting any Error. But the data*.list is intact it does not change to data1.list....No idea..It should be the case...right/???? Smilie
# 38  
Old 09-03-2012
Try this...

What is exact value of data*.list..?

Code:
$ echo "data*.list" | sed -e "s/data\*/data1/g"
data1.list

Last edited by pamu; 09-03-2012 at 07:07 AM.. Reason: added info...
# 39  
Old 09-03-2012
Hi,
ummmm, this script used to run on some 120 files and take ~ 20 minutes for each file.Smilie

I was just wondering if I can submit parallel jobs..I meant script can run on several file at the same time..Not sure, it accessible..??


Thanks
Poooja

---------- Post updated at 06:11 AM ---------- Previous update was at 05:55 AM ----------

What is exact value of data*.list..?
In present script, it is data15.list. I ran the script and it picked it 15 only....no conversion to data1.list Smilie

Code:
$ echo "data*.list" | sed -e "s/data\*/data1/g"
data1.list

[/QUOTE]


I am not sure how to use it..?? I tried several combination, did not work..Smilie
Code:
[pooja04@cmslpc13 extra]$ echo "data*.list" | sed -e "s/data\*/data1/g" card_Data2011AB_Zee_40GeV  > file3
[pooja04@cmslpc13 extra]$ op file3 
[pooja04@cmslpc13 extra]$ op file3
[pooja04@cmslpc13 extra]$ echo "data*.list" | sed -e "s/data\*/data1/g" > card_Data2011AB_Zee_40GeV  
[pooja04@cmslpc13 extra]$ op card_Data2011AB_Zee_40GeV

# 40  
Old 09-03-2012
Quote:
Originally Posted by nrjrasaxena
I was just wondering if I can submit parallel jobs..I meant script can run on several file at the same time..Not sure, it accessible..??


Thanks
Poooja

---------- Post updated at 06:11 AM ---------- Previous update was at 05:55 AM ----------

What is exact value of data*.list..?
In present script, it is data15.list. I ran the script and it picked it 15 only....no conversion to data1.list Smilie

Code:
$ echo "data*.list" | sed -e "s/data\*/data1/g"
data1.list


For performing operation on files separately you need to run different instances of the script...

assuming you have files.. like below..-

data1.txt, data12.txt, data1sd3.txt, datasfdf.txt

Code:
$echo "data1.txt
data12.txt
data1sd3.txt
datasfdf.txt" | sed  's/data[a-zA-Z0-9]*/data1/g'
data1.txt
data1.txt
data1.txt
data1.txt

Let me know if you have any other files than this....
# 41  
Old 09-03-2012
Quote:
Originally Posted by nrjrasaxena
...
Code:
...
      if [ $k > 0 ]; then
...

You have this in two places, should be if [ "$k" -gt 0 ]; then
Don't think it explains your error, but better to get it right, and if you are using [...] always use double quotes around variables
# 42  
Old 09-04-2012
Quote:
Originally Posted by pamu
Let me know if you have any other files than this....
Hi,
I have files format like data1.list, data2.list data3.list etc..

thanks,
pooja

---------- Post updated at 05:17 AM ---------- Previous update was at 05:16 AM ----------

Quote:
Originally Posted by 244an
always use double quotes around variables

Hi,
thanks for the correction..ummm, may i ask the significance of having "" ..???

pooja
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