awk loop - substr and sub query

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1. Shell Programming and Scripting

awk and substr

Hello All; I have an input file 'abc.txt' with below text: 512345977,213458,100021 512345978,213454,100031 512345979,213452,100051 512345980,213455,100061 512345981,213456,100071 512345982,213456,100091 512345983,213457,100041 512345984,213451,100011 I need to paste the first field...

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HELP : awk substr

Hi, - In a file test.wmi Col1 | firstName | lastName 4003 | toto_titi_CT- | otot_itit - I want to have only ( colones $7,$13 and $15) with code 4003 and 4002. for colone $13 I want to have the whole name untill _CT- or _GC- 1- I used the command egrep with awk #egrep -i...

3. Shell Programming and Scripting

awk substr

Hello life savers!! Is there any way to use substr in awk command for returning one part of a string from declared start and stop point? I mean I know we have this: substr(string, start, length) Do we have anything like possible to use in awk ? : substr(string, start, stop) ...

4. Shell Programming and Scripting

Substr with awk

Hi to all, I'm here again, cause I need your help to solve another issue for me. I have some files that have this name format: date_filename.csv In my shell I must rename each file removing the date so that the file name is filename.csv To do this I use this command: fnames=`ls ${fname}|...

5. Shell Programming and Scripting

awk substr

HI I am using awk and substr function to list out the directory names in the present working directory . I am using below code ls -l | awk '{ if ((substr($1,1,1)) -eq d) {print $9 }}' But the problem is i am getting all the files and directories listed where as the requirement i wrote...

6. Shell Programming and Scripting

Help with awk and substr

I have the following to find lines matching "COMPLETE" and extract parts of it using substr. sed -n "/COMPLETE/p" 1.txt | awk 'BEGIN { FS = "\" } {printf"%s %s:%s \n", substr($3,17,3),substr($6,4,1), substr($7,4,1)}' | sort | uniq > temp.txt Worked fine until the numbers in 2nd & 3rd substr...

7. Shell Programming and Scripting

awk substr

Hi I have multiple files that name begins bidb_yyyymm. (yyyymm = current year month of file creation). What I want to do is look at the files and where yyyymm is older than 1 month I want to remove the file from the server. I was looking at looping through the files and getting the yyyymm...

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awk or substr

i have a variable 200612 the last two digits of this variable should be between 1 and 12, it should not be greater than 12 or less than 1 (for ex: 00 or 13,14,15 is not accepted) how do i check for this conditions in a unix shell script. thanks Ram

9. Shell Programming and Scripting

How to use awk substr ?

Hi all, I have a flatfile I would like to get ext = 7950 , how do I do that ? if ($1 == "CTI-ProgramStart") { ext = substr($9,index($9,"Extension")+11,4); But why it is not working ???? Please help . Thanks

10. Shell Programming and Scripting

awk substr?

Sorry if this has been posted before, I searched but not sure what I really want to do. I have a file with records that show who has logged into my application: 2003-03-14:I:root: Log_mesg: registered servername:userid. (more after this) I want to pull out the userid, date and time into...

LEARN ABOUT DEBIAN

bup-margin

bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME

       bup-margin - figure out your deduplication safety margin

SYNOPSIS

       bup margin [options...]

DESCRIPTION

       bup margin  iterates  through  all  objects  in	your  bup repository, calculating the largest number of prefix bits shared between any two
       entries.  This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.

       For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45.  That  means  a  46-bit
       hash  would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
       its first 46 bits.

       The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects.  Since SHA-1 hashes have 160 bits,
       that  leaves 115 bits of margin.  Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
       with far fewer objects.

       If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see	if
       you're getting dangerously close to 160 bits.

OPTIONS

       --predict
	      Guess  the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
	      from the guess.  This is potentially useful for tuning an interpolation search algorithm.

       --ignore-midx
	      don't use .midx files, use only .idx files.  This is only really useful when used with --predict.

EXAMPLE

	      $ bup margin
	      Reading indexes: 100.00% (1612581/1612581), done.
	      40
	      40 matching prefix bits
	      1.94 bits per doubling
	      120 bits (61.86 doublings) remaining
	      4.19338e+18 times larger is possible

	      Everyone on earth could have 625878182 data sets
	      like yours, all in one repository, and we would
	      expect 1 object collision.

	      $ bup margin --predict
	      PackIdxList: using 1 index.
	      Reading indexes: 100.00% (1612581/1612581), done.
	      915 of 1612581 (0.057%)

SEE ALSO

       bup-midx(1), bup-save(1)

BUP

       Part of the bup(1) suite.

AUTHORS

       Avery Pennarun <apenwarr@gmail.com>.

Bup unknown-															     bup-margin(1)

Shell Programming and Scripting