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Exit status of the ksh Script

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# 1  
Old 08-09-2012
Exit status of the ksh Script
Hi

Im trying to write a script that will archive some file using java program.Below is the part of the script that I use and my problem is that the script always return with status 0.Below is part of my script(end part)

purge.ksh

Code:
                echo "No of files before tar : $noOfFilesDir"
                tar -cf $line/$logDate.tar `find $line -type f ! -name "*.tar"`
                noOfFilesTar=`tar -tf $line/$logDate.tar | wc -l`
                echo "No of files in tar : $noOfFilesTar"
                if [ $noOfFilesDir -ne $noOfFilesTar ]
                then
                        echo "Some of the files could not be archived under $line.Please investigate"
                        retVal=1
                else
                        find $line -type f ! -name "*.tar" -exec rm -f {} \;
                fi
        done <"$file"
        rm -f $TAR_LIST_FILE_NAME
fi
echo "\nUnix script exited with code : $retVal"
exit $retVal
) 2>&1 | tee $APP_DIR/logs/purgeFiles_$logDate.log

I call this script from another script and then check the return status and it always return 0 even if the retVal is 1.

Calling script:

ksh purge.ksh
echo $?

The status code is always 0.
Please help as I need to redirect the ouput of the whole script to screen and also to the file and exit the script based on retVal.

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Last edited by Corona688; 08-09-2012 at 12:10 AM..
# 2  
Old 08-09-2012
If this never gets executed then it(retVal) will be what you initialized it to:
Code:
if [ $noOfFilesDir -ne $noOfFilesTar ] then
  echo "Some of the files could not be archived under $line.Please investigate"
  retVal=1



Also try exiting with a "1" like this and see what you get:
Code:
exit 1

# 3  
Old 08-09-2012
Hi

Sorry not for being very clear at first.The java code exit with code 1 and I can see the out put "Unix code exited with output 1" but still $? from calling script shows output code as 0.
# 4  
Old 08-09-2012
As far as i can see from the snippet you set "retVal=1" within a loop. This loop might get executed several times any maybe there is a "retVal=0" above which gets executed later on in another pass of the loop.

I hope this helps.

bakunin
# 5  
Old 08-09-2012
Code:
(
       echo "some"  
       exit 1
) 2>&1   | tee somefile.tmp

After this ? is 0 if tee works (access to write file). But if you remove pipe tee, then you get that exit code which you are trying.
? include always the last command exit status. ( ) is subprocess, so exit exits only that subprocess. After that you have tee.
If you look somefile.tmp, it include word some. So tee works fine = exit 0.
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