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what's wrong with my regex using find

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# 1  
Old 08-02-2012
what's wrong with my regex using find
Code:
#ls json-*
json-lexer.c  json-lexer.h  json-parser.c  json-parser.h  json-streamer.c  json-streamer.h

Code:
#find . -regex '^(json-)[a-z]+.[ch]'

return nothing
# 2  
Old 08-02-2012
The regex option with find is funky to say the least. You have to account for the that leading "./" in the path leading to the file in your regex.

This works, but tweak to your tastes:

Code:
find -regextype awk -regex '.*json-[a-z]+\.[ch]'
./json-streamer.c
./json-parser.h
./json-parser.c
./json-lexer.h
./json-lexer.c

Hope this helps.
# 3  
Old 08-02-2012
I'm not sure. Fortunately this is simple enough no regex is needed.

Code:
find . -name 'json-*.[ch]'

-name always requires the glob to match the entire filename.

This will also work on more systems, since few actually support -regex.
# 4  
Old 08-02-2012
Quote:
Originally Posted by in2nix4life
The regex option with find is funky to say the least. You have to account for the that leading "./" in the path leading to the file in your regex.

This works, but tweak to your tastes:

Code:
find -regextype awk -regex '.*json-[a-z]+\.[ch]'
./json-streamer.c
./json-parser.h
./json-parser.c
./json-lexer.h
./json-lexer.c

Hope this helps.


really strange, haha

---------- Post updated at 09:55 AM ---------- Previous update was at 09:55 AM ----------

Quote:
Originally Posted by in2nix4life
The regex option with find is funky to say the least. You have to account for the that leading "./" in the path leading to the file in your regex.

This works, but tweak to your tastes:

Code:
find -regextype awk -regex '.*json-[a-z]+\.[ch]'
./json-streamer.c
./json-parser.h
./json-parser.c
./json-lexer.h
./json-lexer.c


./ will break my thought
Hope this helps.
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