Shell Programming and Scripting

Hi i am very new to shell scripting.
I have got stuck on a portion on my script.
Problem :

I have 30 logfiles inside /home/test directory.
I need to find the string "@ended today" in all the 30 logfiles and print the name of the files which did not have this string.

i need to this by using any loop.
Can anybody give me any suggestion how to do this? or any logic to apply loop.

My required Output should be like this :

"Name of the file" didnot ended successfullt today.

Code:

#! /bin/bash

for file in *.log
do
    grep -q '@ended today' $file
    [ $? -ne 0 ] && echo "$file -> didnot ended successfullt today"
done

Code:

cd /home/test
fgrep -lv "@ended today" *|awk '{$0=$0 " did not end successfully today"}1'

Thank you very much balajesuri and elixir for your help.
Problem is resolved now.