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Use of cut to extract process name

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# 1  
Old 06-19-2012
Use of cut to extract process name
Hi all,

I am trying to formulate a command to extract a section of the output of ps -ef,

for example I need to extract the 'plt11dm1' of the following output
Code:
oracle   20132     1  0 May12 ?        00:03:30 ora_smon_plt11dm1

I thourght of using
Code:
ps -ef -o comm|grep ora_smon|grep -v grep|cut -c10-30

But it doesnt seem to work when using /etc/bash shell

Any ideas?

thanks in advance,

John
Last edited by Franklin52; 06-19-2012 at 06:29 AM.. Reason: Please use code tags for data and code samples
# 2  
Old 06-19-2012
Code:
| awk -F'_' '{print $NF}'

# 3  
Old 06-19-2012
Hi,

Try the following;

Code:
ps -ef -o comm|grep ora_smon|grep -v grep|awk '{ print $8 }'

Regards

Dave
# 4  
Old 06-19-2012
Hi all,

Thanks but I get a consistent error when I run -o comm

Code:
ps -ef -o comm|grep ora_smon|grep -v grep|awk '{ print $8 }'

Warning: bad syntax, perhaps a bogus '-'? See /usr/share/doc/procps-3.2.7/FAQ

I get this error when I run my command.

---------- Post updated at 10:39 AM ---------- Previous update was at 10:37 AM ----------

If I run;

Code:
ps -ef |grep ora_smon|grep -v grep|awk '{ print $8 }'

then I get

Code:
ora_smon_plt11dm1
ora_smon_plt11cr1
ora_smon_plt10cr1
ora_smon_plt10dm1


Which is nearly there.

But I just need the name, ie plt11dm1 etc..
Last edited by Scrutinizer; 06-19-2012 at 06:41 AM.. Reason: code tags
# 5  
Old 06-19-2012
Try this ..
Code:
$ ps -ef | grep ora_smon| grep -v grep | awk '{split($8,a,"_"); print a[3]}'

# 6  
Old 06-19-2012
thnx for your helpSmilie
# 7  
Old 06-19-2012
Save a process by changing this:
Code:
grep ora_smon| grep -v grep

to this:
Code:
grep [o]ra_smon

Matches the string "ora_smon" but not itself ("[o]ra_smon").
Last edited by gary_w; 06-19-2012 at 03:46 PM..
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