Loop while and until


 
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# 1  
Old 06-08-2012
Loop while and until

maybe you guys have a better way of doing this.

i'm searching a file for a particular month. if the month is not found, i want the script to automatically look for the month before the month that wasn't found.

so if i searched for jun and jun isn't found, i want the script to know to search back for may. if may is also not found, i want the script to go back one more month.

i want this to continue until a month is found.

here is a my script:

SystemDateM contains the month.

Code:
      TOPOFFILE=$(

                                TOPOFFILEHA=$(head -10 data.txt | egrep "^$SystemDateM" | head -1 | awk '{print $1" "$2" "$3}')

                                        PAMONTH=$(case $SystemDateM in
                                        Jan) echo "12" ;; Feb) echo $(( 2 - 1 )) ;; Mar) echo $(( 3 - 1 )) ;; Apr) echo $(( 4 - 1 )) ;; May) echo $(( 5 - 1 )) ;; Jun) echo $(( 6 - 1 )) ;;
                                        Jul) echo $(( 7 - 1 )) ;; Aug) echo $(( 8 - 1 )) ;; Sep) echo $(( 9 - 1 )) ;; Oct) echo $(( 10 - 1 )) ;; Nov) echo $(( 11 - 1 )) ;; Dec) echo $(( 12 - 1 )) ;; esac
                                        })

                                        PAMONTHREV=$(case $PAMONTH in
                                        1) echo "Jan" ;; 2) echo "Feb" ;; 3) echo "Mar" ;; 4) echo "Apr" ;; 5) echo "May" ;; 6) echo "Jun" ;;
                                        7) echo "Jul" ;; 8) echo "Aug" ;; 9) echo "Sep" ;; 10) echo "Oct" ;; 11) echo "Nov" ;; 12) echo "Dec" ;; esac
                                        })

                                if [ -z "${TOPOFFILEHA}" ] ; then

                                        PAMONTHREVA=$(case $PAMONTHREV in
                                        Jan) echo "12" ;; Feb) echo $(( 2 - 1 )) ;; Mar) echo $(( 3 - 1 )) ;; Apr) echo $(( 4 - 1 )) ;; May) echo $(( 5 - 1 )) ;; Jun) echo $(( 6 - 1 )) ;;
                                        Jul) echo $(( 7 - 1 )) ;; Aug) echo $(( 8 - 1 )) ;; Sep) echo $(( 9 - 1 )) ;; Oct) echo $(( 10 - 1 )) ;; Nov) echo $(( 11 - 1 )) ;; Dec) echo $(( 12 - 1 )) ;; esac
                                        })

                                        PAMONTHREV=$(case $PAMONTHREVA in
                                        1) echo "Jan" ;; 2) echo "Feb" ;; 3) echo "Mar" ;; 4) echo "Apr" ;; 5) echo "May" ;; 6) echo "Jun" ;;
                                        7) echo "Jul" ;; 8) echo "Aug" ;; 9) echo "Sep" ;; 10) echo "Oct" ;; 11) echo "Nov" ;; 12) echo "Dec" ;; esac
                                        })

                                        TOPOFFILEH=$(egrep "^${PAMONTHREV}" < data.txt | tail -1 | $AWK '{print $1" "$2" "$3}')

                                        echo "${TOPOFFILEH}"
                                fi


                                )

sample of data.txt:

Code:
Jun  9 01:40:55 sss nagios: Auto-save of retention data completed successfully.
Jun  9 01:52:53 sss rsyslogd: -- MARK --
Jun  9 02:07:53 sss rsyslogd: -- MARK --
Jun  9 02:22:53 sss rsyslogd: -- MARK --


Last edited by SkySmart; 06-08-2012 at 11:42 PM..
# 2  
Old 06-09-2012
You haven't told us which shell you are using, so i suppose you are using Korn shell. If not you will have to adapt the solution to your shell yourself (consider this your penance for not telling us everything we need to know ;-)) ).

You can do this by implementing a function, which accepts a months name and returns the name of the previous month.

The following function accepts the months name (as long as its first three characters match the output of the "%b" directive of date - "Jan", "Feb", etc., case-insensitively) and prints the name of the previous month in the same format (3 characters, first capitalized). It returns the number of the month found this way as integer or 255, if the parameter passed was not a months name.

For instance: "JANUA" will print "Dec" to <stdout> and return "12", "dec" will print "Nov" to <stdout> and return "11", "foo" will print nothing and return "255".

Code:
function f_prevmon
{
typeset mon[1]="Jan"                      # list of months names
typeset mon[2]="Feb"
typeset mon[3]="Mar"
typeset mon[4]="Apr"
typeset mon[5]="May"
typeset mon[6]="Jun"
typeset mon[7]="Jul"
typeset mon[8]="Aug"
typeset mon[9]="Sep"
typeset mon[10]="Oct"
typeset mon[11]="Nov"
typeset mon[12]="Dec"

typeset -i idx=1                           # array index
typeset -L3 -l monbuf=""                   # convert to lowercase, truncate to 3 chars
typeset -L3 -l in="$1"                     # same with first passed parameter

while [ $idx -le 12 ] ; do
     monbuf="${mon[$idx]}"
     if [ "$in" = "$monbuf" ] ; then       # if month is found
          (( idx -= 1 ))                   # get previous one, rotate on 0
          if (( idx == 0 )) ; then
               idx=12
          fi
          print - "${mon[$idx]}"           # to stdout
          return $idx                      # and return
     fi
     (( idx += 1 ))
done
                                           # we get here only if $1 matched nothing
return 255                                 # so return an error
}

A possible program utilizing this function could look like this. It starts looking for a file "/path/to/myfile.Apr.ext", if it does not find it tries "/path/to/myfile.Mar.ext", then "/path/to/myfile.Feb.ext", etc., until it finds a file or has cycled through the whole year, upon which it prints an error message.

Code:
#!/bin/ksh

FPATH=$FPATH:/path/to/f_prevmon


typeset month="Apr"          # some arbitrary starting date
typeset start="$month"         # we need this to avoid infinite loops

while [ ! -e /path/to/myfile.${month}.ext ] ; do
     month=$(f_prevmon $month)
     if [ $? -eq 255 ] ; then
          print - "f_prevmon encountered an unintelligible months name"
          exit 255
     fi
     if [ "$month" = "$start" ] ; then
          print - "we tried all months, but did not find anything. Aborting now."
          exit 255
     fi
done

print - "the file you looked for is: /path/to/myfile.${month}.ext"

exit 0

I hope this helps.

bakunin
This User Gave Thanks to bakunin For This Post:
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