Variable increment (of some sort)


 
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# 8  
Old 05-24-2012
Please read my code. It shows you how to do exactly that. It even shows you how to loop over the contents of a list -- for X in $NEWLIST

The code you gave:
Code:
NEWLIST=$NEWLIST" "SERVER_NAME

is wrong. Without the $ in front of SERVER_NAME, it will append the string SERVER_NAME to the list, not the variable.

You'll end up with a list of "SERVER_NAME SERVER_NAME SERVER_NAME SERVER_NAME"
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SWAPBDDVAR(3)							   BDD FUNCTIONS						     SWAPBDDVAR(3)

NAME
swapbddvar - swaps two contiguous variables. ORIGIN
This software belongs to the ALLIANCE CAD SYSTEM developed by the ASIM team at LIP6 laboratory of Universite Pierre et Marie CURIE, in Paris, France. Web : http://asim.lip6.fr/recherche/alliance/ E-mail : alliance-users@asim.lip6.fr SYNOPSYS
#include "bdd101.h" void swapbddvar( BddSystem, Variable ) bddsystem *BddSystem; bddvar Variable; PARAMETERS
BddSystem The bdd system. Variable The variable to swap. DESCRIPTION
swapbddvar swaps the variable number Variable with the variable number Variable + 1, in the bdd system BddSystem. If a null pointer is given, the default bdd system is used. This function is usefull for the bdd nodes reordering. RETURN VALUE
swapbddvar returns nothing. ERRORS
"variable xxx out of range, error !" The Variable and Variable + 1, must be valid variables number. EXAMPLE
#include "bdd101.h" bddsystem *BddSystem; bddnode *BddNode1; bddnode *BddNode2; BddSystem = createbddsystem( 100, 1000, 100, 50000 ); BddNode1 = addbddvar( (bddsystem *)0, 0 ); BddNode2 = addbddvar( (bddsystem *)0, 0 ); swapbddvar( (bddsystem *)0, 0 ); destroybddsystem( (bddsystem *)0 ); SEE ALSO
bdd(1) BUG REPORT
This tool is under development at the ASIM department of the LIP6 laboratory. We need your feedback to improve documentation and tools. ASIM
/LIP6 October 1, 1997 SWAPBDDVAR(3)