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Extract paragraphs under conditions

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# 1  
Old 05-07-2012
Data Extract paragraphs under conditions
Hi all,
I want to extract some paragraphs out of a file under certain conditions.
- The paragraph must start with 'fmri'
- The paragraph must contain the string 'restarter svc:/system/svc/restarter:default'

My input is like that :
Code:
fmri         svc:/system/vxpbx:default
state_time   Wed Mar 21 08:49:43 2012
logfile      /var/svc/log/system-vxpbx:default.log
restarter    svc:/system/svc/restarter:default
dependency   require_all/none svc:/system/filesystem/local (online)
 
fmri         svc:/application/management/common-agent-container-1:default
name         Cacao, a common Java container for JDMK/JMX based management solution
enabled      false
dependency   require_all/none svc:/milestone/multi-user (online)

And I should have this in output :
Code:
fmri         svc:/system/vxpbx:default
state_time   Wed Mar 21 08:49:43 2012
logfile      /var/svc/log/system-vxpbx:default.log
restarter    svc:/system/svc/restarter:default
dependency   require_all/none svc:/system/filesystem/local (online)

I came up to the following solution but the issue I have is that only the first paragraph is displayed. I guess it's due to the fact that the command does not loop and stops at the first occurence found :
Code:
awk '/fmri/{s=x}{s=s$0"\n"}/restarter/{p=1}/^$/ && p{print s;exit}' svcs-l_spsol03.out

Thanks for your help !
# 2  
Old 05-07-2012
Try:
Code:
awk -vRS= '/^fmri/&&/restarter/' file

# 3  
Old 05-07-2012
Didn't think about this vRS possibility, thanks a lot !
# 4  
Old 05-07-2012
the command's not vrs. the -v specifies variable, RS specifies record separator. When it's empty, awk splits on blank lines.
# 5  
Old 05-07-2012
Quote:
Originally Posted by Corona688
the command's not vrs. the -v specifies variable, RS specifies record separator. When it's empty, awk splits on blank lines.
Thanks for your comment
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