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Changing the column for a row in a text file and adding another row

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Top Forums Shell Programming and Scripting Changing the column for a row in a text file and adding another row
# 1  
Old 04-26-2005
Changing the column for a row in a text file and adding another row
Hi,
I want to write a shell script which increments a particular column in a row from a text file and then adds another row below the current row with the incremented value .
For Eg .
if the input file has a row :
abc xyz lmn 89 lm nk o p

I would like the script to create something like this :
abc xyz lmn 89 lm nk o p
abc xyz lmn 90 lm nk o p

Incrementing column 4th and creating a new row for it .

awk ' { ++$4 } print $0 ' inputfile

Now this will increment the column but I dont know how to create a new row without disturbing the original row .
Infact I would like to get 10 rows like that , with 4th column of each row getting incremented . I guess once I know how it can be done for 1 row, i can put that in for loop .

Any pointers or help would be appreciated .
# 2  
Old 04-26-2005
Code:
$ more process.awk
BEGIN { c = 0 }

{ print $0; lastrow = $0 }

END { while ( c < 10 ) {
   $0 = lastrow
   ++$4
   print $0
   lastrow = $0
   ++c
   }
}
$ more tmp/foofile
abc xyz lmn 89 lm nk o p
$ awk -f process.awk tmp/foofile
abc xyz lmn 89 lm nk o p
abc xyz lmn 90 lm nk o p
abc xyz lmn 91 lm nk o p
abc xyz lmn 92 lm nk o p
abc xyz lmn 93 lm nk o p
abc xyz lmn 94 lm nk o p
abc xyz lmn 95 lm nk o p
abc xyz lmn 96 lm nk o p
abc xyz lmn 97 lm nk o p
abc xyz lmn 98 lm nk o p
abc xyz lmn 99 lm nk o p

Cheers
ZB
# 3  
Old 04-26-2005
Thanks Zazzybob . I appreciate your response . I tried your script but I am getting this error .

abc xyz lmn 89 lm nk o p
awk: can't set $0
record number 1

Do you know what could cause this ?
# 4  
Old 04-26-2005
Actually I got it . I had to use nawk . Thanks again for response . I appreciate it .
# 5  
Old 04-27-2005
Hi,
I was trying this script today . If I had to add another column and add 24 instead of 1 on that column and add new row after that , how can I do it .
For example if the input line is :
abc xyz lmn 89 lm nk o p 2 p

and I want

abc xyz lmn 89 lm nk o p 2 p
abc xyz lmn 90 lm nk o p 26 p
abc xyz lmn 91 lm nk o p 50 p
.
.
.
.
upto 10 lines .

I tried adding 24 to the $9 in the script above , like this .

BEGIN { c = 0 }

{ print $0; lastrow = $0 }

END { while ( c < 10 ) {
$0 = lastrow
++$4
$9 = $9 + 24
print $0
lastrow = $0
++c
}
}

But the result says :
abc xyz lmn 89 lm nk o p 2 p

1 24
1 24 1 24
1 24 1 25 24
1 24 1 26 24 24
1 24 1 27 24 24 24
1 24 1 28 24 24 24 24
1 24 1 29 24 24 24 24 24
1 24 1 30 24 24 24 24 48
1 24 1 31 24 24 24 24 72
1 24 1 32 24 24 24 24 96

I think I am messing up the addition in the column 9 .
Whats the correct way to do it ?
Any help would be appreciated .

Thanks.
# 6  
Old 04-29-2005
It worked for me:
Code:
$ more foofile
abc xyz lmn 89 lm nk o p 2 p
$ more process.awk
BEGIN { c = 0 }

{ print $0; lastrow = $0 }

END { while ( c < 10 ) {
$0 = lastrow
++$4
$9 = $9 + 24 
print $0
lastrow = $0
++c
}
}
$ awk -f process.awk foofile 
abc xyz lmn 89 lm nk o p 2 p
abc xyz lmn 90 lm nk o p 26 p
abc xyz lmn 91 lm nk o p 50 p
abc xyz lmn 92 lm nk o p 74 p
abc xyz lmn 93 lm nk o p 98 p
abc xyz lmn 94 lm nk o p 122 p
abc xyz lmn 95 lm nk o p 146 p
abc xyz lmn 96 lm nk o p 170 p
abc xyz lmn 97 lm nk o p 194 p
abc xyz lmn 98 lm nk o p 218 p
abc xyz lmn 99 lm nk o p 242 p

I wonder what is the significant difference between our systems.
# 7  
Old 04-29-2005
Ok, I got a similar (but not exactly identical) result by leaving out "{ print $0; lastrow = $0 }". Are you sure there isn't a typo somewhere? Try copying the code directly from your message, because that code works fine.
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