Calling function from another bash script


 
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# 8  
Old 04-04-2012
Something like this:

Code:
$ cat test.sh
#! /bin/bash
echo $(dirname $(readlink -f $0))
$
$ ./test.sh
/home/user
$

# 9  
Old 04-04-2012
Using the following works
Code:
bashPath=${0%/*}

But the one suggested below seems more robust to me
Code:
$(dirname $(readlink -f $0))

# 10  
Old 04-04-2012
You can combine the merits of both into something slightly more efficient than using dirname in backticks:

Code:
V=$(readlink -f "$0")
V="${V%/*}"

# 11  
Old 04-04-2012
Quote:
Originally Posted by Corona688
You can combine the merits of both into something slightly more efficient than using dirname in backticks:

Code:
V=$(readlink -f "$0")
V="${V%/*}"

Can you explain to be the merits of one versus the other, and how the one you constructed combines the merits of both, if you please?
# 12  
Old 04-05-2012
It is faster to use shell builtins than external utilities when you can, especially when processing tiny amounts of information. External utilities can run quite quickly once loaded but take time and resources to start and finish.
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