Shell Programming and Scripting

Hi,

You could try this:

Code:

awk -F\" '{sub(/[^0-9]*/,x,$9);print $9}' infile

and if this file format is consistent, then you could perhaps use spaces a a field separator

Code:

a=$(printf "%s" "$line" | awk '{print $5}')
a=${a#$}

Or use probably more efficiently, use the read statement in the loop:

Code:

while read x x x x amount x
do
  a=${amount#$}
  echo "$a"
done < infile

Hi,

Can you please explain what is being done in the above three codes.
Thanks

Or back to using "tr".

Code:

a=`echo "$line" | cut -f9  -d '"' | cut -c32-41 | tr '$' ' '`

Thanks Methyl !! This works fine.

But I need a clarification. Before, I have used 'tr' in two different expresions similar to 'sed' in the below code and it didn't work.

Code:

a=`echo "$line" | cut -f9  -d '"' | cut -c32-41`
a=`echo "$a" | sed 's/$/ /g'`

Does piping it into one single expression made the difference ? Or is there any other reason ?

Nr. 1 uses a double quote as the field separator and then deletes any non-digit from the start of field 9 and then prints field 9

Nr.2 uses any number of spaces as field separator and then prints the fifth column, which is the number with a $-sign

Nr.3 I figured you would probably be using a loop tot read the file line by line in your shell script, so I showed an alternative loop that would do the same without external programs and would then therefore be the fastest solution.

No. Just tried it with two lines using "tr" and it still works.

The "sed" is awkward because $ is special to "sed".
You can get it to work if you have enough backslashes.

Code:

a=`echo "${a}" | sed -e "s/\\\\$/ /g"`

Ps. Somebody posted a solution earlier which didn't have enough backslashes.

That's because of both the double quotes and those pesky backticks (I don't understand why anyone would still want to use them, unless they are forced to by their ancient shell).

Code:

a=$(echo "$a" | sed -e 's/\$//g')

Code:

a=$(echo "$a" | sed -e "s/\\$//g")

Code:

a=`echo "$a" | sed -e 's/\\$//g'`

Code:

a=`echo "$a" | sed -e "s/\\\\$//g"`