Shell Programming and Scripting

Hi guys, i have a script that logs into a range of hosts and runs an update involving apt-get: apt-get update

problem i'm having is, before i do the apt-get, i do a apt-get update. and this process is completed quickly for most servers. but some servers, it can take a while.

my expect script aborts and moves on to the next server if the update isn't done quickly.

i know that the option for "timeout" can be used. but that isn't working as expected. when i use timeout, the script logs into the server, then does nothing until the timeout specified has expired. then it runs the commands its suppose to run. this is not good. i want the script to log into the server, immediately run the command, then exits out of the system only if the command has completed.

Can someone please help me modify this?

below is my script:

Code:

#!/usr/bin/expect -f

if {[llength $argv] < 1 } {

puts "Incorrect arguments. Enter following syntax:\n"
puts " tn <node to telnet to> \n\r"
puts "Example: \n"
puts " tn ottud023 \n\r\n\r"
exit 1

}

set wsname [lindex $argv 0]
set usepas [lindex $argv 1]
set usersname [lindex $argv 2]
set remotecommand [lindex $argv 3]

set displayno 0
set prompt "(%|#|:|]|\\$|%]) $"


spawn ssh $wsname -l $usersname
set spwnid1 $spawn_id

expect {
-i $spwnid1
"(yes/no)?" {
send "yes \r"
}
"assword" {
send "$usepas \r"
}
}

set prompt "(%|#|\\$|%]) $"

expect -re $prompt
send -- "$remotecommand \r"
expect "assword"
send -- "$usepas\r"
expect -re $prompt
send -- "exit \r"

where did you put the timeout?