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converting column to row

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# 1  
Old 03-04-2012
converting column to row
Hi everyone..

I have a list of values in a file...


1.2345e-1
2.282828e+
3.2341e-1
1.1223445e-1

I am interested in converting this column to a row..

1.2345e-1 2.282828e+ 3.2341e-1 1.1223445e-1

can anyone pls help?? I am a liunx newbie..




Thanks..
# 2  
Old 03-04-2012
Hi kjha,

Code:
$ awk 'BEGIN { ORS = " " } { print }' infile

Regards,
Birei
# 3  
Old 03-04-2012
There is always this:

Code:
awk  '{ printf( "%s ", $1 ); } END { printf( "\n" ); }' input-file >output-file

# 4  
Old 03-04-2012
Code:
tr '\n' ' ' < infile

or
Code:
sed -e 'N;N;N;s/\n/ /g' infile

# 5  
Old 03-04-2012
Code:
paste -sd" " inputfile

# 6  
Old 03-04-2012
Code:
xargs < infile

# 7  
Old 03-05-2012
Quote:
Originally Posted by Scrutinizer
Code:
xargs < infile

I would suggest caution with this idiom.

In this specific case, where a single row/line of output is desired, if the actual data is large enough, it's possible that echo could be invoked more than once.

In the generic case, a line in the data that looks like a command option could silently yield incorrect results.

Regards,
Alister
These 2 Users Gave Thanks to alister For This Post:
Junaid Subhani Scrutinizer
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