Shell Programming and Scripting

Hi ,

I am trying to create shell script which will help me to compare file name in two folder.
There is a multiple file store in 2 folder.I want to compare that with the name.
If all the file are same then send a mail that "all date is same"

if not then create one log file which contain non-matching file name and send that file with the subject "all contain are not same.

I have tried to compare two file but dont know how to create log file and send a mail.Please find the below script and help me to complete this.

Thanks....

Check into the command 'comm', which takes 2 files or pipes of binary sorted lines, and marks them for one of three columns: a-only, b-only or both. It slides lines left to columns 2 and 3 using 1 or 2 tabs. If you option it -3, it removes all lines in the both column, -13 says remove a and both, leaving no tabs and just what is in file b only. Think of it as robust set arithmetic. In ksh and bash, a neat form sorting on a generated name pipe is:

Code:

( export LC_ALL=C ; comm -13 <( sort file-a ) <(sort file-b ) )

The LC_ALL not C can upset newer sort versions so the sort order can be very strange if not broken.

You can easily post-process the comm output to differentiate a-not-b from b-not-a. The sort input does not need to be a file, it could be:

Code:

comm -3 <(
    cd dir-a ; find * -type f | sort
  ) <(
    cd dir-b ; find * -type f | sort
  )| sed '
        s/^\t/B:/    # \t here represents an actual tab in the sed script
        t
        s/^/A:/

Hi DGPickett,

Thanks... for your quick response...But, I am not sure what you are trying to say and how it will create logfile and send the mail.Please explain me in detail.

Thanks....

Your script in pawing through files and dirs seeing which are not present in both. Comm can do that in bulk, wholesale, identifying which are not present in both. You can tee the output to a log file as you pipe it to mail:

Code:

export zid=$(date "+MissingFiles-%Y-%m-%d-%H%M%S") LC_ALL=C
comm -3 <(
     cd dir-a ; find * -type f | sort
   ) <(
     cd dir-b ; find * -type f | sort
   )| sed '
         s/^\t/B:/    # \t here represents an actual tab in the sed script
         t
         s/^/A:/
 ' | tee $zid_log.txt
) | mail -s $zid you@your_domain

Hi DGPickett,
Again I would like to thank you for your help and explanation….
The requirement is something like that; I am getting a file every month which need to be compare with the last month file.
1. New File is storing in some location in zip formate.I wanted to unzip that and store in some other location.
2. Old file is available in other location like archive folder. Which is used for comparison with new file?
3. I wanted to compare this two file and create the log and send sending the mail. Which is working?
4. After this process overwrite the old file with the new for next month comparison.
One more help: could you please explain the first line of the code which you provided.
export zid=$(date "+MissingFiles-%Y-%m-%d-%H%M%S") LC_ALL=C


Looking for the help on this issue.

Thanks....