Passing arguments from a bash shell script to a command


 
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# 8  
Old 02-24-2012
Thank you again! I had hammered out pretty much the same thing (except with && instead of ||), and was trying to figure out what to replace $* with, and whether to quote it -- so after reading that I'm sorted. You've been incredibly helpful.
# 9  
Old 02-24-2012
The difference between "$*" and "$@" is that "$*" will split where the spaces are, not where the arguments are. "$@" will keep the original arguments intact.
# 10  
Old 02-24-2012
Got it -- thanks!
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