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Renaming multipe files

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# 1  
Old 01-04-2012
Renaming multipe files
Hi, I have these list of files from with the following filename format (the last 3 characters are in julian days). I want the year info retained added with sequence number 01-12 to represent the month. any suggestion on how to automate the renaming process. many thanks.
Code:
original filenames  desired output
1999001.res         199901.res
1999032.res         199902.res
1999060.res         199903.res
1999091.res         199904.res
1999121.res         199905.res
1999152.res         199906.res
1999182.res         199907.res
1999213.res         199908.res
1999244.res         199909.res
1999274.res         199910.res
1999305.res         199911.res
1999335.res         199912.res
2000001.res         200001.res
2000032.res         200002.res
2000061.res         200003.res
2000092.res         200004.res
.. to
2007335.res         200712.res

# 2  
Old 01-04-2012
Run below command without red part ( |sh" ) frist , if looks fine, then run the whole command to rename files.
Code:
ls *.res |awk -F \. 'function JD2MON(YY,JD){ 
               split("31 28 31 30 31 30 31 31 30 31 30 31",m," ")
               mm = 1; JD+=0
	       if (YY%4==0 && (YY%100!=0 || YY%400==0)) m[2] = 29 
               while (JD > m[mm]) {
                     JD -= m[mm++]
               }
               return sprintf ("%4d%02d",YY,mm)
           }
           { year=substr($1,1,4)
             JulianDay=substr($1,5,3)
             MON=JD2MON(year,JulianDay)
             printf "mv %s %s\n", $0 , MON FS $2
           }'  |sh

mv 1999001.res 199901.res
mv 1999032.res 199902.res
mv 1999060.res 199903.res
mv 1999091.res 199904.res
mv 1999121.res 199905.res
mv 1999152.res 199906.res
mv 1999182.res 199907.res
mv 1999213.res 199908.res
mv 1999244.res 199909.res
mv 1999274.res 199910.res
mv 1999305.res 199911.res
mv 1999335.res 199912.res
mv 2000001.res 200001.res
mv 2000032.res 200002.res
mv 2000061.res 200003.res
mv 2000092.res 200004.res
mv 2007335.res 200712.res

This User Gave Thanks to rdcwayx For This Post:
ida1215
# 3  
Old 01-04-2012
bash code:
  1. #! /bin/bash
  2.  
  3. days_reg=( 1 32 60 91 121 152 182 213 244 274 305 335 )
  4. days_leap=( 1 32 61 92 122 153 183 214 245 275 306 336 )
  5. months=( 01 02 03 04 05 06 07 08 09 10 11 12 )
  6.  
  7. for file in `ls *res | sort -n`
  8. do
  9.     st=`echo $file | cut -c5-7`
  10.     for mt in `seq 0 11`
  11.     do
  12.         if [ $st -eq ${days_reg[$mt]} -o $st -eq ${days_leap[$mt]} ]
  13.         then
  14.             mv $file `echo $file | cut -c1-4`${months[$mt]}.res
  15.             continue
  16.         fi
  17.     done
  18. done
This User Gave Thanks to balajesuri For This Post:
ida1215
# 4  
Old 01-04-2012
thanks guys, tried both options. worked seamlessly,Smilie
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