Process file every minute


 
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# 36  
Old 01-23-2012
@methyl,

Thank you for replying, this printf is not doing what is should have done.

Code:
awk 'BEGIN { INTERVAL=120;    "date +%s"|getline sec;
    NEXT=sec+120;}

    {
        if(sec >= NEXT)
        {
           printf( "\nSummary\n" );
           for( x in agcount )
              printf( "%s,%d\n", x, agcount[x] ) | "sort";

           # Clear out old values
           for( x in agcount)
                   delete agcount[x];

           NEXT=sec+120;
        }

Smilie
I am not sure where this is going wrong, can I please get someone to help me with this.
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PIPE(2) 							System Calls Manual							   PIPE(2)

NAME
pipe - create an interprocess communication channel SYNOPSIS
pipe(fildes) int fildes[2]; DESCRIPTION
The pipe system call creates an I/O mechanism called a pipe. The file descriptors returned can be used in read and write operations. When the pipe is written using the descriptor fildes[1] up to 4096 bytes of data are buffered before the writing process is suspended. A read using the descriptor fildes[0] will pick up the data. It is assumed that after the pipe has been set up, two (or more) cooperating processes (created by subsequent fork calls) will pass data through the pipe with read and write calls. The shell has a syntax to set up a linear array of processes connected by pipes. Read calls on an empty pipe (no buffered data) with only one end (all write file descriptors closed) returns an end-of-file. Pipes are really a special case of the socketpair(2) call and, in fact, are implemented as such in the system. A signal is generated if a write on a pipe with only one end is attempted. RETURN VALUE
The function value zero is returned if the pipe was created; -1 if an error occurred. ERRORS
The pipe call will fail if: [EMFILE] Too many descriptors are active. [ENFILE] The system file table is full. [EFAULT] The fildes buffer is in an invalid area of the process's address space. SEE ALSO
sh(1), read(2), write(2), fork(2), socketpair(2) BUGS
Should more than 4096 bytes be necessary in any pipe among a loop of processes, deadlock will occur. 4th Berkeley Distribution August 26, 1985 PIPE(2)