Shell Programming and Scripting

Hi balajesuri,

The code below:

Code:

for x in `ls`; do [ `stat -c%y $x | cut -c1-16 | sed 's/[- :]//g'` -ge `date -d"yesterday" +%Y%m%d%H%M` ] && echo $x; done

is used to get the FILES in the directory, what about if I want to get the logs in a file. I've tried to substitute

Code:

`cat /home/subdirectory/file`

to

Code:

`ls`

, but I think this cannot be


Please advise,
rymnd_12345

Do you want to print the output (list of files satisfying the condition) in a file instead of screen?
OR
Do you want contents of each of the files listed in a separate file?

If it's the former case, just redirect the output to a filename. Try putting this at the end > list_of_files.txt

If it's the latter case, replace && echo $x; donewith && cat $x; done > temp.txt. You'll get a message on screen cat: temp.txt: input file is output file. Just ignore it. It's trying to copy contents of temp.txt into itself. If you wish, you may also write a condition to skip temp.txt.

Hi balajesuri,

Suggestion for the latter case may do.

Thanks so much!



Br,
rymnd_12345